----Rounding issues for iOS development

method One:

-(NSString *) notrounding: (float) Price afterpoint: (int) position{

nsdecimalnumberhandler* roundingbehavior = [ nsdecimalnumberhandler Decimalnumberhandlerwith roundingmode:nsrounddown scale:position raiseonexactness:no raiseonoverflow:no RaiseOnUnderflow:NO Raiseondividebyzero:no];

nsdecimalnumber *ouncesdecimal;

nsdecimalnumber *roundedounces;

 

ouncesdecimal = [[Nsdecimalnumber alloc] Initwithfloat:price ];

Roundedounces = [Ouncesdecimal decimalnumberbyroundingaccordingtobehavior: Roundingbehavior];

[Ouncesdecimal release];

return [nsstring stringwithformat:@ "%@", Roundedounces ];

}

Explain the parameters:

Price: Numbers that need to be processed,

Position: Keep the decimal point,

and then call

float s = 0.126;

NSString *sv = [self notrounding:s afterpoint:2 ];

NSLog (@ "SV =%@", SV );

The output is: SV = 0.12

The following describes the key parameters of Nsdecimalnumberhandler initialization: DecimalnumberhandlerwithRoundingmode:nsrounddown,

The Nsrounddown represents is only to be placed.

The parameter position of scale represents a few digits after the decimal point is retained.

What do I do if I just get into it, for example, float 0.162 want 0.17? , there is a table on the development document that is treated as a reserved decimal point. I believe that we can see the following:

Method Two:

round (12345.6789)   result: 12346

round (12345.6789*100)/100  result: 12345.68

The second is the result I want, but I do not understand this simple rounding to make so complicated, there should be better, I remember in other languages with:round (12345.6789,2) You can achieve rounding to two decimal places.

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----Rounding issues with iOS development