A Java program that throws exceptions recursively __j2se

    * * * Testexception.java * December 6, 2017 afternoon 2:37:47 * Copyright 2017 Fosun Financial.
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    * @author Flyer * @version 1.0/Package testfuxing; /** * Function Description * @version * @author Flyer December 6, 2017 afternoon 2:37:47 * @since 1.8/public class Te
    
        stexception {static int i = 0;
        public static void Main (String args[]) {Testdigui ();
            private static void Testdigui () {try {int t = i/0;
                catch (Exception e) {//new runtimeexception (e);
                    if (I < 3) {System.out.println ("before recursion:" + i);
                    i++; TesTdigui ();
                System.out.println ("Recursive:" + i);
                } i = 0;
            System.out.println ("Final execution:" + i);
 }
        }
    }

The output is:

Before recursion: 0
Before recursion: 1
Before recursion: 2
Last implemented: 0
After recursion: 0
Last implemented: 0
After recursion: 0
Last implemented: 0
After recursion: 0
Last implemented: 0

private static void TestExceptionOrder1 () {
int q[]= {1,0,8,19};
try {
for (int m:q) {
int t = 100/m;
System.out.println ("T:" + t);
}
}
catch (Exception e) {
System.out.println ("Final execution:" + E);
}
}

private static void TestExceptionOrder2 () {
int q[]= {1,0,8,19};

for (int m:q) {
try {
int t = 100/m;
System.out.println ("T:" + t);
}
catch (Exception e) {
E.printstacktrace ();
System.out.println ("Final execution:" + E);
}
}
}

The first function throws an exception and does not follow

t:100
Last implemented: Java.lang.ArithmeticException:/by zero

The second function throws an exception, which does not affect the subsequent execution of the

t:100
Last implemented: Java.lang.ArithmeticException:/by zero
T:12
T:5