ACM--HDOJ 2024--c Language Legal identifier--string

Hdoj Title Address: Portal

C-Language legal identifiersTime limit:2000/1000 MS (java/others) Memory limit:65536/32768 K (java/others) Total Submission (s): 59528 Accepted Submission (s): 23541

Problem description Enter a string to determine whether it is a valid identifier for C.

Input data contains multiple test instances, the first row of the data is an integer n, which indicates the number of test instances, followed by n rows of input data, each of which is a string of not more than 50 in length.

Output outputs one row for each set of input data. If the input data is a valid identifier for C, output "yes", otherwise, output "no".

Sample Input

312ajffi8x_aff  ai_2

Sample Output

Noyesno

#include <stdio.h> #include <string.h> #include <map> #include <iostream> #include < Algorithm>using namespace Std;int Main () {   int n;   string S;   cin>>n;   int flag=1;   GetChar ();   while (n--) {      flag=1;      Getline (cin,s);      if (S.size () ==0) {        printf ("no\n");         flag=0;      } else if (! ( (s[0]>= ' A ' &&s[0]<= ' z ') | | (s[0]>= ' A ' &&s[0]<= ' Z ') | | s[0]== ' _ ')) {        printf ("no\n");         flag=0;      } else{for        (int i=1;i<s.size (); i++) {            if ((s[i]>= ' 0 ' &&s[i]<= ' 9 ') | | s[i]== ' _ ' | |               (s[i]>= ' A ' &&s[i]<= ' z ') | | (s[i]>= ' A ' &&s[i]<= ' Z '))) {            }else{               flag=0;               printf ("no\n");               Break      ;      }}} if (flag)        printf ("yes\n");}   }

ACM--HDOJ 2024--c Language Legal identifier--string