Adjust the array order so that the odd number is preceded by even numbers--the sword refers to the offer

Title: Enter an array of integers to implement a function to adjust the numbers in the array so that all the odd digits are in the first half of the array, and all the even digits are in the second half of the array.

Code:

1#include <stdio.h>2 BOOLIsEven (intN)3 {4     return(N &1) ==0;5 }6 voidReorder (int*pdata, unsignedintLengthBOOL(*func) (int))7 {8     if(PData = = NULL | | length = =0)9         return;Ten     int*pbegin =PData; One     int*pend = pData + Length-1; A      while(Pbegin <pEnd) -     { -          while(Pbegin < pEnd &&!func (*pbegin))//If the previous pointer points to a number that is odd thepbegin++; -          while(Pbegin < PEnd && func (*pend))//If the number pointed to by the following pointer is even -pend--; -         if(Pbegin <pEnd) +         { -             inttemp = *Pbegin; +*pbegin = *pEnd; A*pend =temp; at         } -     } -      - } - intMain () - { in     inta[8] = {5,1,6,2,3,7,8,Ten }; -Reorder (A,8, IsEven); to      for(inti =0; I <8; i++) +printf"%3d", A[i]); -printf"\ n"); the     return 0; * } $ /*Panax Notoginseng 5 1 7 3 2 6 8 - Please press any key to continue ... the  + */

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Adjust the array order so that the odd number is preceded by even numbers--the sword refers to an offer