Android determines whether the character is Chinese, Korean, or Japanese

We often need to judge in the program whether a character is a character in CJK (Chinese, Japanese, Korean) language.

For example, in Contacts, the program needs to determine the language of the contact name.

Today, we will introduce a method for determining the language of a character in NameSplitter.

Take determining whether the character is Chinese as an example.

First, you can use the guessFullNameStyle function to determine the language of the character (using UnicodeBlock );

    public static int guessFullNameStyle(String name) {        if (name == null) {            return FullNameStyle.UNDEFINED;        }        int nameStyle = FullNameStyle.UNDEFINED;        int length = name.length();        int offset = 0;        while (offset < length) {            int codePoint = Character.codePointAt(name, offset);            if (Character.isLetter(codePoint)) {                UnicodeBlock unicodeBlock = UnicodeBlock.of(codePoint);                if (!isLatinUnicodeBlock(unicodeBlock)) {                    if (isCJKUnicodeBlock(unicodeBlock)) {                        // We don't know if this is Chinese, Japanese or Korean -                        // trying to figure out by looking at other characters in the name                        return guessCJKNameStyle(name, offset + Character.charCount(codePoint));                    }                    if (isJapanesePhoneticUnicodeBlock(unicodeBlock)) {                        return FullNameStyle.JAPANESE;                    }                    if (isKoreanUnicodeBlock(unicodeBlock)) {                        return FullNameStyle.KOREAN;                    }                }                nameStyle = FullNameStyle.WESTERN;            }            offset += Character.charCount(codePoint);        }        return nameStyle;    }

 

    private static int guessCJKNameStyle(String name, int offset) {        int length = name.length();        while (offset < length) {            int codePoint = Character.codePointAt(name, offset);            if (Character.isLetter(codePoint)) {                UnicodeBlock unicodeBlock = UnicodeBlock.of(codePoint);                if (isJapanesePhoneticUnicodeBlock(unicodeBlock)) {                    return FullNameStyle.JAPANESE;                }                if (isKoreanUnicodeBlock(unicodeBlock)) {                    return FullNameStyle.KOREAN;                }            }            offset += Character.charCount(codePoint);        }        return FullNameStyle.CJK;    }

 

Secondly, if the result is CJK, we need to further judge whether it is Chinese, Japanese, or Korean.

    /**     * If the supplied name style is undefined, returns a default based on the     * language, otherwise returns the supplied name style itself.     *      * @param nameStyle See {@link FullNameStyle}.     */    public static int getAdjustedFullNameStyle(int nameStyle) {        String mLanguage = Locale.getDefault().getLanguage().toLowerCase();        if (nameStyle == FullNameStyle.UNDEFINED) {            if (JAPANESE_LANGUAGE.equals(mLanguage)) {                return FullNameStyle.JAPANESE;            } else if (KOREAN_LANGUAGE.equals(mLanguage)) {                return FullNameStyle.KOREAN;            } else if (CHINESE_LANGUAGE.equals(mLanguage)) {                return FullNameStyle.CHINESE;            } else {                return FullNameStyle.WESTERN;            }        } else if (nameStyle == FullNameStyle.CJK) {            if (JAPANESE_LANGUAGE.equals(mLanguage)) {                return FullNameStyle.JAPANESE;            } else if (KOREAN_LANGUAGE.equals(mLanguage)) {                return FullNameStyle.KOREAN;            } else {                return FullNameStyle.CHINESE;            }        }        return nameStyle;    }

Well, that's probably the case. I wrote a small Demo using Eclipse, hoping to help you ~

Source code link:

Http://pan.baidu.com/share/link? Consumer id = 4025849919 & uk = 2953765628