Android Press two times back key to exit the app

Objective
Welcome everyone I share and recommend useful code Snippets ~ ~
Statement
Welcome reprint, but please keep the original source of the article:
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rainy season o mo away:http://blog.csdn.net/luckkof

Body

<span Style= "font-size:10px;"    >private static Boolean isexit = false;    private static Boolean Hastask = false;    Timer texit = new timer ();            TimerTask task = new TimerTask () {@Override public void run () {isexit = false;        Hastask = true;         }    }; @Override public boolean onKeyDown (int keycode, keyevent event) {System.out.println ("Tabhost_index.java Onkeydo        WN ");                if (keycode = = Keyevent.keycode_back) {if (Isexit = = False) {Isexit = true;                Toast.maketext (This, "press the back key again to exit the application", Toast.length_short). Show ();                if (!hastask) {Texit.schedule (Task, 2000);                }} else {finish ();            System.exit (0);    }} return false; }</span> 

<span style= "font-size:10px;" >private long waitTime = +;  Private long touchtime = 0; @Overridepublic boolean onKeyDown (int keycode, keyevent event) {if (event.getaction () = = Keyevent.action_down && Keyevent.keycode_back = = keycode) {Long currenttime = System.currenttimemillis (); if (currenttime-touchtime) >= wait Time) {Toast.maketext (context, "Press Exit program again", Toast.length_short). Show (); touchtime = CurrentTime;} else {finish (); System.exit (0);} return true;}    Return Super.onkeydown (KeyCode, event);} </span>