Android two times prompts to exit the application, and android two times to exit

Android two times prompts to exit the application, and android two times to exit
Reprinted please indicate: http://blog.csdn.net/u012637501 Android two prompts to exit the application, the core idea is: in the main Activity re-write onKeyDown method, which is a callback method, that is, when the user presses a button on the keyboard, we can determine which button is pressed Based on the keyboard code. Then, determine the time interval (for example, 3 s) between the two buttons to determine whether to exit the application by pressing the return key twice. The specific implementation code is as follows:

1. /* --- OnKeyDown method: press the two return keys to exit --*/
2.  Public BooleanOnKeyDown (IntKeyCode, KeyEvent event ){
3. LongPeriod;
4. If(KeyCode = event. KEYCODE_BACK) // press the return key.
5. {
6. Period = System. currentTimeMillis ()-mExitTime; // interval between two presses
7. If(Period> 3000) // two presses within 3 s to exit.
8. {
9. Toast. makeText (This, "Exit the program again", Toast. LENGTH_SHORT). show ();
10. Mexico time = System. currentTimeMillis ();
11. }
12. Else
13. {
14. Finish (); // end Activity (main), that is, exit the application
15. }
16. Return True;
17. }
18. Return Super. OnKeyDown (keyCode, event );
19. }
20. }

Running result: two times of pressing the return key within 3 seconds, exit the program. Otherwise, the first time you press the return key is invalid, and you are prompted to re-press again to exit the program.