Application of reinterpret_cast in programming

In some cases, int needs to be converted to uint and double to int64_t to meet the interface type requirements. However, after this conversion, data loss may occur. If you only want to read the original data to adapt to the interface, you can use reinterpret_cast. For example, [cpp] # include <stdio. h> # include <stdint. h> int main () {int64_t I = 0; double d = 1.1; int64_t j = reinterpret_cast <int64_t &> (d ); double j2 = reinterpret_cast <double &> (j); int64_t k = static_cast <int64_t> (d); double k2 = static_cast <double> (k ); printf ("org = % lf, reintterpret forw (double => int64_t) = % ld \ t, reintterpret back (int64_t => double) = % lf \ n", d, j, j2); printf ("org = % lf, static forw (double => Int64_t) = % ld \ t, static back (int64_t => double) = % lf \ n ", d, k, k2);} compiled output result: [SQL] [xiaochu. yh @ tfs035040 cpp] $. /. out org = 1.100000, reintterpret forw (double => int64_t) = 4607632778762754458, reintterpret back (int64_t => double) = 1.100000 org = 1.100000, static forw (double => int64_t) = 1, static back (int64_t => double) = 1.000000. After static_cast is used, the precision data is lost. Reinterpret_cast is a binary conversion that does not care about the data semantics. When using reinterpret, note that the storage space needs to be sufficient. If you convert double to int32_t, the final result will fail.