Python is just getting started. I think pythonturtle is really cute ~ I tried to draw a "heart", but I thought the method was too stupid & gt; & lt; I 'd like to ask my friends, is there any other way to draw a "heart" in python/pythonturtle? When I started python, I thought python turtle was really cute ~ I tried to draw a "heart", but I thought the method was too stupid> <I want to ask my friends, is there any other way to draw a "heart" in python/python turtle?
Reply content:
from turtle import *def curvemove(): for i in range(200): right(1) forward(1)color('red','pink') begin_fill()left(140)forward(111.65)curvemove()left(120)curvemove()forward(111.65)end_fill()done()
From turtle import * From turtle import *
Pensize (1)
Color ('black', 'red ')
Speed (2)
Up ()
Goto (-12,100)
Down ()
Begin_fill ()
Left (90)
Circle (1, 120,180)
Circle (360, 70.529)
Left (0, 38.942)
Circle (360, 70.529)
Circle (1, 120,180)
End_fill ()
Up ()
Goto (-250,-150)
Down ()
from pylab import*t=linspace(0,2*pi,100)x=sin(2*t) + 2*sin(t)y=-cos(2*t)-2*cos(t)fill(x,y,'r')show()
The heart is not painted, but there is a rose I forgot to post the code before, and now I want to add it. I forgot to post the code before, and now I want to add it.
For I in range (1 ):
Def paint (ang, r, ang2): # drawing function
Turtle. penup ()
Turtle. setheading (ang)
Turtle. pendown ()
Turtle. circle (r, ang2)
Import turtle
Turtle. speed (9)
Turtle. color ("white") # Set
Turtle. pensize (7)
Turtle. penup ()
Turtle. goto (50,-50)
Turtle. pendown ()
Turtle. dot (200, "pink") # Draw background
Turtle. penup ()
Turtle. goto (50, 86.6)
Ang =-1, 150
R = 300.
Ang2 = 46
For j in range (21): # Loop
Paint (ang, r, ang2) # draw an arc
Ang2-= 25
Paint (ang + ang2 + 25, r,-ang2) # Roll Back
Ang2 + = 25
Ang + = 66
R = r * 0.9
The idea is: draw an arc, roll back about 1/3, turn, reduce the radius, draw an arc... keep repeating...
Video Portal Python Rose _ life
Remind me of the code-based student. I read your documents. It seems that you and I have selected the same elective course from the same school. But I have handed in this assignment, so you can ask me if you don't understand it.
The instructor will beat you up.
(Too many □') Too many characters. No one can trust me for 35 reasons. I will give you some ideas ~ However, I may not be able to help you in the last exam weeks...
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import sysimport math def frange(start, end, step=1.0):if step > 0:while start < end:yield start start += stepelif step < 0:while start > end:yield start start += stepelse:raise ValueError('range() step must not be zero')def f(x, y, z):a = x*x + 9.0/4*y*y + z*z - 1 return a*a*a - x*x*z*z*z - 9.0/80*y*y*z*z*z def h(x, z):for y in frange(1.0, 0.0, -0.001):if f(x, y, z) <= 0:return y return 0.0if __name__ == '__main__':for z in frange(1.5, -1.5, -0.1):for x in frange(-1.5, 1.5, 0.05):v = f(x, 0, z)if v <= 0:y0 = h(x, z)ny = 0.01nx = h(x + ny, z) - y0 nz = h(x, z + ny) - y0 nd = 1.0/math.sqrt(nx*nx+ny*ny+nz*nz)d = (nx + ny - nz)*nd*0.5 + 0.5sys.stdout.write('.:-=+*#%@'[int(d*5)])else:sys.stdout.write(' ')sys.stdout.write('\n')
Use python matplotlib to draw a Cartesian heart-shaped line
Import numpy as np Import numpy as np
Import pylab as plt
From matplotlib import colors
A = [[] for I in range (1000)]
I = 0
While I <1000:
J = 0
While j <1000:
X =-1.8 + 0.003 * I
Y =-1.4 + 0.0028 * j
Z = y ** 2 + (-x-(y ** 2) ** 0.33333) ** 2
If z <= 1:
A [I]. append (0.9)
Else:
A [I]. append (0.0)
J = j + 1
I = I + 1
Cmap = colors. ListedColormap (['white', 'pink'])
Im = plt. imshow (a, cmap = cmap, interpolation = "bicubic ")
Plt. show ()
