Automatic initialization of C + + variable--important

Source: Internet
Author: User

For automatic initialization of built-in variables

Code Listing 1:

#include <stdio.h>#defineCONST 100int*P1;inta[2];intb;Static intC;main () {intD; Static inte; intf[2]; int*P2; printf ("const=%d\n", CONST); printf ("a[0]=%d\n", a[0]); //printf ("*p1=%d\n", *P1);printf"b=%d\n", B); printf ("c=%d\n", c); printf ("d=%d\n", D); printf ("e=%d\n", E); printf ("f[0]=%d\n", f[0]); printf ("*p2=%d\n",*p2);}
Press CTRL + C to copy the code

Output:

const=100

A[0]=0

B=0

C=0

d=2514932

E=0

f[0]=1307813

*p2=457819009

The data area holds the initialized global variables, static variables (both global and local), constants.

Uninitialized data area (Uninitializeddata SEGMENT,BSS) holds globally uninitialized variables. BSS data is initialized to 0 or null before the program starts executing. The variable in the BSS segment occupies only one sign bit in the target file, and the compiler does not allocate space for the variable, so so-called "initialize to 0" refers to the request for space at the link stage and is initialized to 0. Only the initialized global variables are to occupy the size of the target file.

In other words global variables, static variables (both global and local), constants not explicitly initialized are initialized by default when 0 or null.

If you try to print *p1, a segment error occurs because P1 points to a null address.

While a local non-static variable is not explicitly initialized when it is a random number, it is generally a large number.

Automatic initialization for class-type variables

A class-type variable invokes the default constructor for initialization, whether it is a global or local scope.

The so-called "default constructor" is the constructor that refers to an empty argument.

Code Listing 2:

class a{public:    int  value;    A () {        cout<<"intitialize a"<<Endl;        Value=3;    }}; A A1; int Main () {    A A2;    cout<<a1.value<<Endl;    cout<<a2.value<<Endl;     return 0 ;}

Output:

Intitialize A
Intitialize A
3
3

If a class does not explicitly define any constructors , the compiler automatically generates an empty argument for it, called the composite default constructor. The composition default constructor initializes members with 3 rules:

1. When an object is in a global scope or is a static local object, the built-in member variable of the class is initialized to 0.

2. When an object is defined in a local scope, the built-in member variable of the class is not initialized to 0.

Code Listing 3:

class a{public:    int  value;}; A A1; int Main () {    A A2;     Static A A3;    cout<<a1.value<<Endl;    cout<<a2.value<<Endl;    cout<<a3.value<<Endl;     return 0 ;}

Output:

0
2510836
0

3. Initializes a class-type member according to its own (composite) default constructor . -Important

Code Listing 4:

classa{ Public:    intvalue; A () {Value=5; }};classb{ Public:    intvalue; A;  }; B B1;intMain () {B b2; cout<<b1.value<<"\ t"<<b1.a.value<<Endl; cout<<b2.value<<"\ t"<<b2.a.value<<Endl; return 0;}

Output:

0 5
134514784 5

Code Listing 5:

classa{ Public:    intvalue;};classb{ Public:    intvalue; A;}; B B1;intMain () {B b2; cout<<b1.value<<"\ t"<<b1.a.value<<Endl; cout<<b2.value<<"\ t"<<b2.a.value<<Endl; return 0;}

Output:

0 0
134514736-1081710584

If the class explicitly provides a constructor with parameters, the compiler will no longer generate null arguments for it's constructor. At this point, the cannot define a class type variable with an empty argument . The following code is wrong:

 class   a{ public  :  int      value; a (  int   i): value (i) {} };  class   b{ public  :  int      value; A a;//calls the constructor of an empty argument};  int      main () {a A;  return  0  ;}  

Transferred from: http://www.cnblogs.com/zhangchaoyang/articles/2671551.html

Automatic initialization of C + + variable--important

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