Basic Practice hex to Decimal

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It seems that the int type will not exceed, but ...

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Algorithm

1 /*Problem Description2 Enter a positive hexadecimal number string that does not exceed 8 bits from the keyboard, converting it to a positive decimal number after the output. 3 Note: 10~15 in hexadecimal numbers are denoted by uppercase letters A, B, C, D, E, F, respectively. 4 Sample Input5 FFFF6 Sample Output7 65535*/8 ImportJava.util.*;9  Public classMain {Ten      Public Static voidMain (string[] args) { OneString st =NewScanner (system.in). nextline (); ASystem.out.println (Long.parselong (St, 16)); -     } -}

Learning Supplement

Integer class

static int parseint (String s)//将字符串参数作为有符号的十进制整数进行解析

static int parseint (String s,int radix)//resolves the string argument to a signed integer using the cardinality specified by the second parameter. Returns a decimal integer (radix represents a binary)

Example:

parseint ("0", 10) returns 0

parseint ("473", 10) returns 473

parseint ("0", 10) returns 0

parseint ("-ff", 16) return-255

parseint ("1100110", 2) returns 102

parseint ("2147483647", 10) returns 2147483647

parseint ("2147483648", 10) return-2147483648

parseint ("2147483648", 10) throws NumberFormatException

parseint ("99", 8) throws NumberFormatException

parseint ("Kona", 10) throws NumberFormatException

parseint ("Kona", 27) return 411787

Long class

Static Long Parselong (string s)//resolves the String argument to a signed decimallong

Static Long Parselong (String s,int radix)//resolves the String parameter to a signed long , cardinality specified by the second parameter returns a decimal long

Basic Practice hex to Decimal