C + + arrays and pointers

Let's look at the following code:

#include <iostream> #include <stdio.h> #include <string>using namespace Std;int main () {int time[] = { 1,2,3};int *q; q = time;cout<<*q<< "" <<q<<endl;char arr[]= "Hello World"; string *p;string str[] = {"Linux", "Unix"};p = str;cout<<*p<< "" <<p<<endl;char* pc;pc = arr;cout<<arr<< "" <<*pc<<endl;cout<<pc<<endl;string s = "Linux"; string *ps;ps = &s;cout<<ps<<* Ps<<endl;return 0;}

Here is the result of the operation:

1 0x7fff6de21a20
Linux 0x7fff6de21a00
Hello World H
Hello World
0X7FFF6DE219F0 Linux
Explain:

I've always been a little puzzled by the pointers. So when it's okay to write this code specifically, the code is not difficult. But it's very helpful for me to know pointers and data.

Examples of time,str and s of all the output, according to the description in the book, it is easy to determine the output of the data. The only thing that confuses me is char* and char[].

In C and C + + if the direct assignment char* p= "Hello World", is equivalent to char arr[]= "Hello World"; p = arr. Here if you do not specifically declare "Hello World" as a string, it is considered a character array.

P points to the first address of the array. Output *p, which is the first character of the output. If you output p, the entire string is printed. This is the difference between the char* and non-char pointers I know.

C + + arrays and pointers