C + + converts integers to strings

#include <iostream>using namespace std;intMainintargcChar**argv) {     intA,b,c=0;     Iint i,j; Chard[6],e[6]; CIN>>A;  while(a>=Ten) {b=a%Ten; A=a/Ten; D[c++]=b+'0'; } d[c++]=a+'0'; D[C]=' \0'; I=(Signed) strlen (d);  for(j=0; j<i;j++) {E[i-j-1]=D[j]; } E[i]=' \0';
cout<<e<<endl; return 0; }

Idea: The integer is continuously taken to the remainder, the remainder plus the character type ' 0 ' to obtain the remainder of the character format, and the data is continuously written to an array.

Because the array is written backwards, it needs to be flipped over.

C + + converts integers to strings