C + + decimal conversion to binary instance code _c language

The topic content: Converts decimal integers to binary numbers.

Input Description: The input data contains no more than 50 integers n ( -231<n<231).

Output Description: For each n, enter an n value with a 11-bit width right-aligned, then output "-->", and then output the binary number. The output of each integer n, which occupies one row independently.

Topic Analysis: The specific way to convert a number from decimal to binary is the number is 2, and the result is either 1 or 0, which corresponds to the last digit of the binary, and then the number divided by two, the resulting quotient again to the 2 remainder, the result is the penultimate digit of the corresponding binary. And so on, know that the result divided by 2 is 0.

Reference code:

Copy Code code as follows:

#include <iostream>
#include <fstream>
#include <string>
#include <algorithm>
using namespace Std;

string S;
int main (int argc,char * argv[])
{
int n;
while (Cin>>n)
{
if (n==0)
{
cout<< "0-->0\n";
Continue
}
S= "";
for (int a=n;a;a=a/2)
{
s=s+ (a%2? ') 1 ': ' 0 ');
}
Std::reverse (S.begin (), S.end ());
const char *SSS=S.C_STR ();
Cout.width (11);
cout<<n<< (n<0?) -->-":"--> ") <<sss<<" \ n ";
}
System ("pause");
return 0;
}

Effect as shown: