C # Call and implement WebService, pure hand-built! _c# Tutorial

Why do you want to do it purely by hand, because the other side is done in C + +, I followed the WSDL they gave to achieve a webservice, and they can not be called at all. The question of whether they call the problem or the WSDL definition is not a test.

The weak side of the sad urge ... We can only go with them. Don't mention it.

First use C # to call each other's webservice.
Adding Web service references is invalid because of the C + + implementation used by the other party ... Adding WSDL directly to the caller does not recognize ...

Had to hand-built, but fortunately, C # strong enough.

The HttpWebRequest class can simply implement the WebService invocation.

First create SOAP package content manually

Copy Code code as follows:

string soap =
"<soapenv:envelope xmlns:soapenv=\" http://schemas.xmlsoap.org/soap/envelope/\ "xmlns:down=\" http:// Down.wsdl.position.mdd.ailk.com\ "xmlns:in=\" http://in.object.down.wsdl.position.mdd.ailk.com\ ">"
+ "<soapenv:Header/>"
+ "<soapenv:Body>"
+ "<TestFunc>"
+ "<object>test message</object>"
+ "</TestFunc>"
+ "</soapenv:Body>"
+ "</soapenv:Envelope>";

Constructing HttpWebRequest Objects

Copy Code code as follows:

HttpWebRequest request = (HttpWebRequest) httpwebrequest.create ("http://localhost:8088/");
Request. method = "POST";
Request. ContentType = "Text/xml; Charset=utf-8 ";
Request. Headers.add ("SOAPAction", "/testfunc");
byte[] BTS = Encoding.UTF8.GetBytes (SOAP);

Send Request

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Request. ContentLength = data. Length;
Stream writer = Request. GetRequestStream ();
Writer. Write (data, 0, data. Length);
Writer. Close ();

Get return information

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StreamReader sr = new StreamReader (Request. GetResponse (). GetResponseStream (), Encoding.UTF8);
String retxml = Sr. ReadToEnd ();
Sr. Close ();

Then, as defined by the WSDL, parsing the returned XML string is good.

Of course, hand-played to create is tired ...

If it is a standard webservice, direct a string of str = Serv.testfunc ("");

Don't mention it.

C # Implementation WebService to the other caller
As I understand it, the WebService is soap, which is essentially a TCP short connection.

The solution is to use C # to implement a TCP server, and then manually analyze the request content.

Copy Code code as follows:

Start listening port
MyListener = new TcpListener (Ipaddress.parse (LISTENIPADDR), listenport);
Mylistener.start ();

Receive the connection and get the request content

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Accept New Connection
Socket mysocket = Mylistener.acceptsocket ();
String sbuffer = "";
byte[] breceive = new byte[2048];

Receive Request content
int i = mysocket.receive (breceive, breceive.length, 0);
Sbuffer = Encoding.ASCII.GetString (breceive);

Process only "POST" request types
if (sbuffer.substring (0, 4)!= "POST")
{
Return
}

Intercept the Soap:body section

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string soap = "<?xml version=\" 1.0\ "encoding=\" utf-8\ ">\n";
int istartpos = Sbuffer.indexof ("<soap:Body>", 1);
int istoppos = Sbuffer.indexof ("</soap:Body>", 1);

if (Istartpos > 0)
{
Soap = soap + sbuffer.substring (istartpos, Istoppos-istartpos + 9);
}

Analyze request content Here's a little bit.

The structure of the returned message is as follows.

Construct the message body content first

Copy Code code as follows:

string ret = string. Format (
""
+ "<soapenv:envelope xmlns:soapenv=\" http://schemas.xmlsoap.org/soap/envelope/\ "xmlns:down=\" http:// Down.wsdl.position.mdd.ailk.com\ "xmlns:out=\" http://out.object.down.wsdl.position.mdd.ailk.com\ ">\n"
+ "<soapenv:header/>\n"
+ "<soapenv:body>\n"
+ "<testrsp>\n"
+ "<object resultcode=\" 0\ "/>\n"
+ "</testrsp>\n"
+ "</soapenv:body>\n"
+ "</soapenv:Envelope>"
);
byte[] bytes = Encoding.ASCII.GetBytes (ret);

Construct message headers

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Structural head
String Smimetype = "text/html";
String shttpversion = "http/1.1";
String sbuffer = "";

if (smimeheader.length = 0)
{
Smimeheader = "text/html"; Default text/html
}

Sbuffer = sbuffer + shttpversion + "OK" + "\ r \ n";
Sbuffer = Sbuffer + "server:cx1193719-b\r\n";
Sbuffer = Sbuffer + "Content-type:" + smimetype + "\ r \ n";
Sbuffer = Sbuffer + "accept-ranges:bytes\r\n";
Sbuffer = Sbuffer + "Content-length:" + itotbytes + "\r\n\r\n";

Byte[] heads = Encoding.ASCII.GetBytes (Sbuffer);

Then send it to each other and close the socket.

Copy Code code as follows:

Mysocket.send (heads, heads. Length, 0);
Mysocket.send (bytes, bytes. Length, 0);

Mysocket.close ();