C # rounding in one method directly obtains the integer digits

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Rounding

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1         public static decimal Round(decimal d, decimal unit)2         {3             decimal rm = d % unit;4             decimal result = d - rm;5             if (rm >= unit / 2)6                 result += unit;7             return result;8         }

 

Method 1

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1         public static decimal Jinyi(decimal d, decimal unit)2         {3             decimal rm = d % unit;4             decimal result = d - rm;5             if (rm > 0)6                 result += unit;7             return result;8         }

 

Directly integer

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1         public static decimal Quzheng(decimal d, decimal unit)2         {3             decimal rm = d % unit;4             decimal result = d - rm;5             return result;6         }

 

 

 

Call Method

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1 int cou = 3; 2 string uit = string. empty; 3 int cou = int. parse (dt. rows [0] ["decimal places"]. toString (); 4 if (cou = 0) 5 {6 uit = "1"; 7} 8 else 9 {10 uit = "0. "; 11 for (int I = 1; I <cou; I ++) 12 uit + =" 0 "; 13 uit + =" 1 "; 14} 15 16 Jinyi (num, decimal. parse (uit); 17 Round (num, decimal. parse (uit); 18 Quzheng (num, decimal. parse (uit ));