C # several frequently used string interceptions,

C # several frequently used string interceptions,

Http://www.cnblogs.com/VicHuang/archive/2011/10/26/2225376.html

 

String str = "123abc456 ";
Int I = 3;
1. Take the first I character of the string.
Str = str. Substring (0, I); // or str = str. Remove (I, str. Length-I );
2 remove the first I character of the string:
Str = str. Remove (0, I); // or str = str. Substring (I );
3. Start from the right side with I characters:
Str = str. Substring (str. Length-I); // or str = str. Remove (0, str. Length-I );
4. Remove the I characters from the right:
Str = str. Substring (0, str. Length-I); // or str = str. Remove (str. Length-I, I );
5. If "abc" exists in the string, remove it.
Using System. Text. RegularExpressions;
String str = "123abc456 ";
String a = "abc ";
Regex r = new Regex ();
Match m = r. Match (str );
If (m. Success)
{
// Take one of the two below.
Str = str. Replace (,"");
Response. Write (str );
String str1, str2;
Str1 = str. Substring (0, m. Index );
Str2 = str. Substring (m. Index + a. Length, str. Length-a.Length-m.Index );
Response. Write (str1 + str2 );
}
6. If the string contains "abc", replace it with "ABC"
Str = str. Replace ("abc", "ABC ");

**************************************** ********

String str = "adcdef"; int indexStart = str. IndexOf ("d ");

Int endIndex = str. IndexOf ("e ");

String toStr = str. SubString (indexStart, endIndex-indexStart );

C # The question of intercepting the last character of a string!

Str1.Substring (str1.LastIndexOf (",") + 1 );

C # truncate the last character of the string

K = k. Substring (k. Length-1, 1 );

C language ^ how to use

A1 = 0x01; // 0000 0001
A2 = 0x00; // 0000 0000
A3 = 0x03; // 0000 0011
A4 = 0x02; // 0000 0010

B1 = a1 ^ a2; // 0000 0001
B2 = a1 ^ a3; // 0000 0010
B3 = a1 ^ a4; // 0000 0011

^ XOR operator. The bitwise value is 0 and the difference is 1. See the example above.

//
Examples of simple and practical problems:
====================================
======= A ======= B =========
There are two circuits on the top. The two switches are a and B respectively. The opening status is \ [1], and the closing status is/[0].
If both circuits are enabled or disabled.
If a turns on [1], B turns off [0], and circuit 1 Powers on
=====================
If a disables [0], B enables [1], and circuit 2 powers on.
====================================
In summary, the circuit fails in the and B states simultaneously [0]. When a and B are different, the power is charged [1].

C language ^ how to use

A1 = 0x01; // 0000 0001
A2 = 0x00; // 0000 0000
A3 = 0x03; // 0000 0011
A4 = 0x02; // 0000 0010

B1 = a1 ^ a2; // 0000 0001
B2 = a1 ^ a3; // 0000 0010
B3 = a1 ^ a4; // 0000 0011

^ XOR operator. The bitwise value is 0 and the difference is 1. See the example above.

//
Examples of simple and practical problems:
====================================
======= A ======= B =========
There are two circuits on the top. The two switches are a and B respectively. The opening status is \ [1], and the closing status is/[0].
If both circuits are enabled or disabled.
If a turns on [1], B turns off [0], and circuit 1 Powers on
=====================
If a disables [0], B enables [1], and circuit 2 powers on.
====================================
In summary, the circuit fails in the and B states simultaneously [0]. When a and B are different, the power is charged [1].