C language determines the leap year between 0 and 3000

C language determines the leap year between 0 and 3000

# Include <stdio. h> int main () {int year, leap = 1; printf ("\ t judge 0 ~ Leap year \ n ") between 3000; printf (" enter 0 ~ Year between 3000 \ n "); flag: scanf (" % d ", & year); // enter the year if (year> 0 & year <= 3000) // one run for four years, one run for a hundred years, and one run for four hundred years {if (year % 4! = 0) leap = 0; else if (year % 100! = 0) leap = 1; if (year % 400! = 0) leap = 0; if (leap) // leap is 1, which is a leap year printf ("% d is", year); else printf ("% d is not ", year); printf ("a leap year. \ n "); goto flag;} else printf (" input error. Enter 0 ~ Year between 3000 \ n "); goto flag; return 0 ;}

Note: flag is the position of the tag goto flag to continue running.