C language method of converting 16 binary numbers to strings (improved)

Yesterday wrote a method, can be embedded C commonly used uint8_t data converted to a character, but the program has a warning, embarrassing attack is very uncomfortable, so in today solve the problem. Yesterday's Blog
Char in C is a byte, or 8 bits, that can be represented as a number of 2 16 binary. But the first bit is the sign bit, and the microcontroller uses the C language often does not involve negative numbers, so more common is to use unsigned char (unsigned char), and then defined as uint8_t (typedef unsigned char uint8_t;), This can be expressed in 8 bits as 2 16 binary number, such as 1111 1110 is 0xFE, if you need not 16 binary number, but a character, then you can use the following method to implement the 16 binary to character.

#include <stdio.h>#include <stdlib.h>typedef unsigned Charuint8_t;CharHextoch (uint8_t old); uint8_t Hextochar (uint8_t temp);intMain () {inti =0; uint8_t data[5]={0x12,0x34,0x56,0xAB,0xEF}; uint8_t str[Ten]; uint8_t dst[Ten]; for(i =0; i<5; i++) {str[2*i] = data[i]>>4; str[2*i+1] = data[i]&0xf; } for(i =0; i<Ten; i++) {Dst[i] = Hextochar (Str[i]); } for(i =0; i<Ten; i++) {printf("%c\n", Dst[i]); }return 0;} uint8_t Hextochar (uint8_t temp) {uint8_t DST;if(Temp <Ten) {DST = temp +' 0 '; }Else{DST = temp-Ten+' A '; }returnDST;}

Note that the Hextochar function, because the incoming parameters are unsigned, it is not necessary to determine the positive or negative.
Characters that require lowercase can be modified here DST = temp-10 + ' a ';
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C language method of converting 16 binary numbers to strings (improved)