C Language study-a=0 and A==0

Explanations of a=0 and a==0:

if: int a = 0;

So a=0 this expression is false, a==0 this expression is true.

if: int a = 1;

So a=0 this expression is false, a==0 this expression is false.

As an example:

    int a = 0;    if (a = 0)        printf ("True");    else        printf ("False");

output: False.

<span style= "FONT-SIZE:18PX;" >   </span><span style= "font-size:10px;" >int a = 0;    if (a = = 0)        printf ("True");    else        printf ("False");</span>

output: True.

    int a = 1;    if (a = = 0)        printf ("True");    else        printf ("False");

Output: False

    int a = 0;    if (a = 1)        printf ("True");    else        printf ("False");

Output: True

An example of combining the C-language precedence with the binding:

int main () {    int a,b,c;    a=b=c=0;    (1>0?a==0:0>1)? b++:c++;    printf ("%d%d%d\n", A, B, c);    return 0;}

The output is: 010.

int main () {    int a,b,c;    a=b=c=0;    (1>0?a=0:0>1)? b++:c++;    printf ("%d%d%d\n", A, B, c);    return 0;}

The output is: 001

int main () {    int a,b,c;    a=b=c=0;    1>0?a++:(0>1?b++:c++);    printf ("%d%d%d\n", A, B, c);    return 0;}

The output is: 100. It is strange that the values of B and C have not changed. In C, conditional expressions: The binding is right-associative (that is, the right-to-left combination). This is the same as the following program:

int main () {    int a,b,c;    a=b=c=0;    1>0?a++:0>1?b++:c++;    printf ("%d%d%d\n", A, B, c);    return 0;}

The parentheses are removed. The output is verified exactly the same: 100.

Then, the precedence of this bracket () is much higher than the precedence of the conditional expression. So it should be calculated first (0>1?b++:c++) this right? Isn't it?

If yes, then 0>1 is false, then execute C + +, so c=1;

If not, then take the back bracket (0>1?b++:c++) as the front?: A subkey of the statement. Then the first Judge 1>0 is true, so execute a++,a=1; answer output 100. Correct!

Is it like this?? Let's verify it again:

int main () {    int a,b,c;    a=b=c=0;    0>1?a++:(0>1?b++:c++);    printf ("%d%d%d\n", A, B, c);    return 0;}

The output is: 001. Analysis, first Judge 0>1 is false, so execution (0>1?b++:c++), judgment, 0>1 for false so execute c++,c=1; output 001, so the hypothesis is verified.

That should be the case at the moment.

Let's look at an example:

int main () {    int a,b,c;    a=b=c=0;    0>1?a++:0>1?b++:c++?1>0?b++:c++:a++;    printf ("%d%d%d\n", A, B, c);    return 0;}

The output is: 101.

C Language study-a=0 and A==0