1. Print the image as follows:
*
*.*.
*..*..*..
*...*...*...*...
*....*....*....*....*....
*.....*.....*.....*.....*.....*.....
*...... *...... *...... *...... *...... *...... *......
*....... *....... *....... *....... *....... *....... *....... *.......
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Void main () <br/>{< br/> int I, j, k; <br/> int n = 8; <br/> for (I = 1; I <= N; I ++) <br/> {<br/> J = I; <br/> for (k = 1; k <= J; k ++) <br/>{< br/> cout <"*"; <br/> while (j> 1) <br/>{< br/> cout <". "; <br/> j --; <br/>}< br/> J = I; <br/>}< br/> cout <Endl; <br/>}< br/> system ("pause"); <br/>}
2. Print the image as follows:
A
ABC
ABCDE
Abcdefg
Abcdefghi
Abcdefghijk
Abcdefghijklm
Abcdefghijklmno
Abcdefghijklmnopq
Abcdefghijklmnopqrs
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Int _ tmain (INT argc, _ tchar * argv []) <br/>{< br/> int I, j, k; <br/> char C; <br/> for (I = 1; I <= 10; I ++) <br/> {<br/> C = 'a '; <br/> for (j = 10-i; j> = 0; j --) <br/>{< br/> printf (""); <br/>}< br/> for (k = 1; k <= 2 * I-1; k ++) <br/>{< br/> printf ("% C", c); <br/> C ++; <br/>}< br/> printf ("/N"); <br/>}< br/> system ("pause"); <br/> return 0; <br/>}
3. Determine prime numbers
Void F (INT m) <br/>{< br/> int I; <br/> for (I = 2; I <m; I ++) <br/>{< br/> If (M % I = 0) <br/>{< br/> printf ("% d is not a prime number/N ", m); <br/> return; <br/>}< br/> printf ("% d is a prime number/N", M ); <br/> return; <br/>}< br/> // The condition for I termination can also be (INT) SQRT (M * 1.0 ). Must be multiplied by 1.0