Chapter III Homework 3.65

We can draw a stack structure of structure variables from the assembly code given by the topic.

We can see from the assembly code

The difference between the variable T and u 16 address values shows that short s[b] is stored in 16 bytes, and a short variable occupies 2 bytes in memory, so we can infer that

B takes a multiple of four on the integer = 8.
8+4+ (b*2) takes a multiple of four on the integer = 28. So the optional values for B are 8 and 7.
2*a*b takes four of the upper integer to 44, so the optional values for A*b are 21 and 22. So A=3, b=7.

Chapter III Homework 3.65