code block execution order in Java

Code blocks: In Java, code enclosed in {} is called a code block.
Depending on its location and declaration, it can be divided into

Local code block: a local location that defines the life cycle of a variable.
Construct code block: The position of the member in the class, with the code enclosed in {}. The construction code block is executed before each call to the construction method execution.
Function: You can put together the common code in multiple construction methods to initialize the object.
Static code block: The position of a member in a class, with the code enclosed in {}, except that it is decorated with static.
Function: The class is typically initialized.

Static blocks of code, building blocks of code, constructing the order in which the methods are executed?

Execute static code block first

Then execute the construction code block

Last point to construct method

Class fu{    static {        System.out.println ("Fu Static Code");    }    {        System.out.println ("Fu Code");    }    Public Fu () {        System.out.println ("Fu Gouzao");}    } Class Zi extends fu{    static {        System.out.println ("Zi Static Code");    }    {        System.out.println ("Zi Code");    }    Public Zi () {        System.out.println ("Zi Gouzao");}    } public class text{public    static void Main (string[] args) {        Zi Zi = new Zi ();}    }

Output:

Fu static Codezi static codefu Codefu Gouzaozi Codezi Gouzao

　　

code block execution order in Java