AMR loves chemistry, and specially doing experiments. He is preparing for a new interesting experiment.
AMR has n different types of chemicals. Each chemical i have an initial volume of a liters. For this experiment, the AMR have to mix all the chemicals together, but all the chemicals volumes must is equal first. So he task is the chemicals volumes equal.
To does this, the AMR can do different kind of operations.
- Choose Some chemical i and double its current volume so the new volume would be 2ai
- Choose Some chemical I and divide its volume by II (integer division) so the new volume would be
Suppose that each chemical are contained in a vessel of infinite volume. Now AMR wonders what's the minimum number of operations required to make all the chemicals volumes equal?
Input
The first line contains one number n (1≤ n ≤105), the number of chemicals.
The second line contains n space separated integers ai (1≤ a I ≤105), representing the initial volume of the I-th chemical in liters.
Output
Output One integer The minimum number of operations required to make all the chemicals volumes equal.
Sample Test (s) input
3
4 8 2
Output
2
Input
3
3 5 6
Output
5
Note
In the first sample test, the optimal solution are to divide the second chemical volume by both, and multiply the third chem ical volume by and volumes equal 4.
In the second sample test, the optimal solution are to divide the first chemical volume by both, and divide the second and T He third chemical volumes by and twice to make all the volumes equal 1.
The puzzle: By the value of the search handed up on the full ...
1#include <iostream>2#include <cstdio>3#include <cmath>4#include <algorithm>5#include <queue>6#include <cstring>7 #definePAU Putchar (")8 #defineENT Putchar (' \ n ')9 using namespacestd;Ten Const intmaxn=100000+Ten, maxv=100000, inf=-1u>>1; One intVis[maxn],cnt[maxn],stp[maxn],n; AInlineintRead () { - intx=0, sig=1;CharCh=GetChar (); - while(!isdigit (CH)) {if(ch=='-') sig=-1; ch=GetChar ();} the while(IsDigit (CH)) x=Ten*x+ch-'0', ch=GetChar (); - returnx*=Sig; - } -InlinevoidWriteintx) { + if(x==0) {Putchar ('0');return;}if(x<0) Putchar ('-'), x=-x; - intlen=0, buf[ the]; while(x) buf[len++]=x%Ten, x/=Ten; + for(inti=len-1; i>=0; i--) Putchar (buf[i]+'0');return; A } at voidinit () { -n=read (); -queue<pair<int,int> >Q; - for(intI=1; i<=n;i++){ - intNum=read (); Q.push (num, Make_pair0)); - while(!Q.empty ()) { in intX=q.front (). first,y=Q.front (). Second; Q.pop (); - if(x>maxv| | Vis[x]==i)Continue; tovis[x]=i;cnt[x]++;stp[x]+=y; +Q.push (Make_pair (x<<1, y+1)); -Q.push (Make_pair (x>>1, y+1)); the } * } $ intMi=inf;Panax Notoginseng for(intI=0; i<=maxv;i++)if(CNT[I]==N&&STP[I]<MI) mi=Stp[i]; - write (MI); the return; + } A voidWork () { the return; + } - voidprint () { $ return; $ } - intMain () {init (); work ();p rint ();return 0;}
Codeforces Round #312 (Div. 2) C.amr and chemistry