Description of the type constructor parameter in Python

The test code is as follows:

1 classModelmetaclass (type):2     def __new__(cls,name,base,attrs):3Logging.info ("CLS is:"+str (CLS))4Logging.info ("name is:"+STR (name))5Logging.info ("Base is:"+Str (base))6Logging.info ("Attrs is:"+str (attrs))7         returnType.__new__(cls,name,base,attrs)8         Pass9     PassTen  One classModel (dict): A     __metaclass__=Modelmetaclass -     def __init__(self): -         Pass the     Pass -  - defMain (): -m=Model () +  - if __name__=='__main__': +Main ()

Test results:

1INFO:root:cls is:<class '__main__. Modelmetaclass'>2INFO:root:name is: Model3INFO:root:base is:(<type'Dict'>,)4INFO:root:attrs is:{'__module__':'__main__','__metaclass__': <class '__main__. Modelmetaclass','__init__': <function__init__At 0x025c76f0>}

The conclusion is obvious. The CLS is the name of the current class, that is, the class itself. Name is a class that points to modelmetaclass through the __metaclass__ property, which is the class to instantiate, and Modelmetaclass intercepts the instantiation of the class. Base is the base class for the class to instantiate. Attrs is a collection of properties for the class to instantiate.

Description of the type constructor parameter in Python