Jackson JSON converted bean, bean does not have the corresponding value Jackson unrecognized Field

I use Jackson for converting JSON to object class.

JSON:

{ "aaa":"111", "bbb":"222", "ccc":"333" }

Object class:

class Test{    public String aaa;    public String bbb;}

Code:

ObjectMapper mapper = new ObjectMapper();Object obj = mapper.readValue(content, valueType);

My code throws exception like that: org. codehaus. Jackson. Map. exc. unrecognizedpropertyexception: Unrecognized field "CCCC" (class criteria. Result. getgoodsinforesult), not marked as ignorable

And I don't want to add a prop to class test, I just want Jackson convert the exist value whith is also exist in test.

 

 

 

 

Jackson provides a few different mechanisms to configure handling of "extra" JSON elements. Following is an example of encryption ing
ObjectMapperTo notFAIL_ON_UNKNOWN_PROPERTIES.

import org.codehaus.jackson.annotate.JsonAutoDetect.Visibility;import org.codehaus.jackson.annotate.JsonMethod;import org.codehaus.jackson.map.DeserializationConfig;import org.codehaus.jackson.map.ObjectMapper;public class JacksonFoo{  public static void main(String[] args) throws Exception  {    // { "aaa":"111", "bbb":"222", "ccc":"333" }    String jsonInput = "{ \"aaa\":\"111\", \"bbb\":\"222\", \"ccc\":\"333\" }";    ObjectMapper mapper = new ObjectMapper().setVisibility(JsonMethod.FIELD, Visibility.ANY);    mapper.configure(DeserializationConfig.Feature.FAIL_ON_UNKNOWN_PROPERTIES, false);    Test test = mapper.readValue(jsonInput, Test.class);  }}class Test{  String aaa;  String bbb;}

For other approaches, see

Http://wiki.fasterxml.com/JacksonHowToIgnoreUnknown