Java Development Engineer on-machine pen test

Online to see 3 good Java Development engineers on the machine pen questions, there is no answer here to write the answer, for everyone reference.

1, a program, enter 10 integers, and put in the array, the first descending output all the number, and then statistics and output the number of positive, negative and zero

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PACKAGE&NBSP;CN. pigzhu.test;import java.util.scanner;/** *  Console Enter 10 numbers and enter the number of positive and negative  *  @author   Xiaoyezhu * */public class test{public static void main (String[] args) {int a[] = new int[10];int i = 0;int m = 0;int n =  0;/** *  gets 10 numbers in the array, and calculates the number of positive and 0 by the way.  */while (i != 10) {System.out.print ("Please enter" +i+ "number: "); Scanner scan = new scanner (system.in); Int input = scan.nextint (); I++;a[i-1]  = input;//here the first number of arrays is a[1] so the number of i-1./** * 0 to be  */if (input==0) {m++;} if  (input<0) {n++;}} /** *  the array for descending output  */system.out.print ("number entered is: ");for  (int j = 0; j  < a.length-1; j++) {int temp;for  (int k = 0; k <  a.length-j-1; k++) {if  (a[k]<a[k+1]) {Temp = a[k];a[k] = a[k+1];a[K+1] = temp;}}} for  (int k = 0; k < a.length; k++) {System.out.print (a[k]+ " ");} System.out.println (); SYSTEM.OUT.PRINTLN ("Positive number has: " + (10-m-n) + "   " + "negative numbers have:  " +n+ "   " + "0 are:    "+m+");}}

2.

Implement a simple English-Chinese weather converter: Enter the weather condition in table 1 The first letter of the English word, according to the input to determine the weather conditions, and output the Chinese form of the weather. The user can re-enter the conversion and enter N to exit the system. Run effect 1 as shown.

Dry mania	humid	hot	rain
Dry	Moisture	Hot	Rainy

Table 1: Chinese and English comparison of weather conditions

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Figure 1: Run effect

PACKAGE CN. pigzhu.test;import java.util.scanner;/** *  implements a simple Chinese-English weather converter  *  @author  xiaoyezhu  * */public class test{public static void main (String[] args) { SYSTEM.OUT.PRINTLN ("****** welcome to the Mini converter ******");/** * while loop to get the weather converted  */while (true) { System.out.print ("Please enter the first English letter of the Weather condition:"); Scanner scan = new scanner (system.in); String s = scan.next ();if  (S.equals ("D")) {System.out.println ("dry");} else if  (S.equals ("M")) {System.out.println ("damp");} else if  (S.equals ("H")) {System.out.println ("hot");} else if  (S.equals ("R")) {System.out.println ("Rain");} ELSE {SYSTEM.OUT.PRINTLN ("Input error, cannot convert!") ");} /** *  continues y on the loop, n jumps out of the loop.  */system.out.print ("Do you want to continue?") (y/n): "); Scanner scan2 = new scanner (system.in); String s2 = scan2.next ();if  (S2.equals ("n")) {break;}} System.out.println ("Exit system!");}}

3 . Use the Java language to implement.

Automatically generates 10 integers (1~100) to find the maximum and minimum values in the generated sequence. Operating effect:

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Figure 1: Run effect

Requirements:

1. Use the Java language;

2. The sort method of the arrays class is not allowed.

PACKAGE&NBSP;CN. Pigzhu.test;import java.util.hashset;import java.util.iterator;import java.util.random;import  java.util.Set;/** *  randomly generate 10 numbers to select the maximum and minimum  *  @author  xiaoyezhu * */public  class test{/** *  the best way to do that is to choose the sort pattern  *  @param  args */public static  void main (String[] args) {/** *  randomly generated 10 numbers exist in set output  */system.out.println ("Randomly generated series is: "); Random r = new random (); Set<integer> set = new hashset<integer> (); while (Set.size ()!=10) {Set.add ( R.nextint (100) +1);} /** *  Traverse out 10 numbers  */iterator<integer> it = set.iterator (); int i =  0;int a[] = new int[10] ;while (It.hasnext ()) {a[i] = it.next (); i++; System.out.print (a[i-1]+ "  ");} SYSTEM.OUT.PRINTLN ();/** *  use a similar selection method to find the maximum, the smallest also the same  */int temp = a[0];for  (int  j = 0; j < a.length; j++) {if  (a[j]>temp) {temp = a[j];}} System.out.println ("The largest number of this series is: " +temp);temp = a[0];for  (int j = 0; j  < a.length; j++) {if  (a[j]<temp) {temp = a[j];}} System.out.println ("The smallest number of this series is: " +temp);}}

Hope to help everyone!

Java Development Engineer on-machine pen test