Java involves byte, short, and char operations

Source: Internet
Author: User
In Java, operations involving the byte, short, and char types will first convert these values to the int type, then perform operations on the int type values, and finally obtain the int type result. Therefore, if two bytes are added, an int value is obtained. To obtain the byte type result, you must explicitly convert the result of this int type to the byte type. For example, the following code may cause compilation failure:
Class BadArithmetic {
Static byte addOneAndOne (){
Byte a = 1;
Byte B = 1;
Byte c = (a + B );
Return c;
    }
}
When you encounter the above code, javac will give the following prompt:
Type. java: 6: possible loss of precision
Found: int
Required: byte
Byte c = (a + B );
                                    ^
1 error
To remedy this situation, the int type result obtained by a + B must be explicitly converted to the byte type. The code is as follows:
Class GoodArithmetic {
Static byte addOneAndOne (){
Byte a = 1;
Byte B = 1;
Byte c = (byte) (a + B );
Return c;
    }
}
This operation can be compiled through javac and generate the GoodArithmetic. class file.

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