Java: Print the magic square __java

Enter a natural number N (2≤n≤9), which requires the output of the following magic square, that is, the edge length is n*n, the element value is 1 to n*n,1 in the upper left corner, in turn the elements in a clockwise direction. When   n=3:
     1    2    3    
     8    9    4    &NBSP
     7    6    5 
Input form "  reads an integer n from the standard input.   
Output form   Print results to standard output. The output matches the required phalanx, each number is 5 characters wide, aligned to the right, and a carriage return is output at the end of each line. &NBSP
"Input sample"   4
"Output sample"      
    1     2    3    4  
   12    13   14    5 
   11   16    15    6   
   10     9    8    7

Realize:

Package Cn.dfeng; Import Java.util.Arrays; Import Java.util.Scanner; public class Maze {enum direction{up, down, right, left;} public int[][] Buidmaze (int n) {int[][] Maze = new Int[n][n ]; For (int[] a:maze) {Arrays.fill (A, 0);} int col = 0; int row = 0; int counter = 1; Direction d = direction.right; while (true) {if (maze[row][col] = = 0) {Maze[row][col] = counter++, switch (d) {case Right:if (col + 1< N &&amp ; Maze[row][col + 1] = = 0) {col + +;} else{d = direction.down; row + +;} break; Case Down:if (row + 1 < n && maze[row + 1][col] = = 0) {row + +;} else{d = direction.left; col-;} break; Case Left:if (col-1 >= 0 && maze[row][col-1] = = 0) {col-;} else{d = direction.up; row--;} break; Default:if (row-1 >= 0 && maze[row-1][col] = = 0) {row-;} else{d = direction.right; col + +;} break; }}else{break;} return maze; public void Printmaze (int[][] maze) {for (int[) row:maze) {for (int i:row) {SYSTEM.OUT.PRintf ("%3d", I); } System.out.println (); }/** * @param args */public static void main (string[] args) {Scanner sc = new Scanner (system.in); SYSTEM.OUT.PRINTLN ("Please input the size of the Maze:"); int size = Sc.nextint (); Maze Maze = new Maze (); int[][] m = maze.buidmaze (size); Maze.printmaze (m); } }