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Being uploaded by the file to make a bad day, sure enough the path and various settings in the web really annoying =
The following is the super small white, and its simple "detailed" solution
1. Clear Purpose:The user uploads the 1.txt file to the server (a folder under Web Engineering)
2. Clear ProcessThe file upload process involves two files, a. jsp file, and a servlet file.
. jsp file (upload.jsp): User Action page = Display file name of text box + File selection button (Browse ... ) + Confirm Upload button
servlet file (Uploadservlet.java): Process file uploads according to the file selected in the. jsp
3. Start tapping the code (lift the table!) ). jsp filepageencoding= "UTF-8"%><! DOCTYPE HTML PUBLIC "-//w3c//dtd HTML 4.01 transitional//en" "Http://www.w3.org/TR/html4/loose.dtd" >Key statements in the. JSP:
Key sentence 1:<form action= "upload.do" enctype= "Multipart/form-data " method= "POST" >//form data in binary data transfer, can be transmitted text Image..
Key sentence 2:<input type= "file" name= "FileName" size= "" "/>//type set to" file "is the document selection button, automatically generate a text box + Select button
servlet file:ImportJava.io.BufferedWriter;ImportJava.io.File;ImportJava.io.FileWriter;Importjava.io.IOException;ImportJava.io.PrintWriter;Importjavax.servlet.ServletException;ImportJavax.servlet.annotation.MultipartConfig;ImportJavax.servlet.annotation.WebServlet;ImportJavax.servlet.http.HttpServlet;Importjavax.servlet.http.HttpServletRequest;ImportJavax.servlet.http.HttpServletResponse;ImportJavax.servlet.http.Part; @WebServlet (name= "Uploadservlet", Urlpatterns = {"/upload.do" }) Public classUploadservletextendsHttpServlet {Private Static Final LongSerialversionuid = 1L; PublicUploadservlet () {Super(); } protected voidDoPost (httpservletrequest request, httpservletresponse response)throwsservletexception, IOException {request.setcharacterencoding ("UTF-8"); Response.setcontenttype ("Text/html;charset=utf-8"); String Path= This. Getservletcontext (). Getrealpath ("/"); //path is the project root directory: (Web project named Test)//D:\tomcat\apache-tomcat-8.0.50-windows-x64\apache-tomcat-8.0.50\webapps\test\ Part part= Request.getpart ("FileName");//Part represents a fileSummarize
String H= Part.getheader ("Content-disposition"); //h is the header of the file to be uploaded: The following (upload the Account.txt file on the desktop)//form-data; name= "FileName"; filename= "C:\Users\ASUS\Desktop\account.txt"//Name the Account.txt file as "NewFile" saved in the serverString fname = "NewFile"; //substring is getting the suffix of the file, renaming but not changing the suffixfname = fname + h.substring (H.lastindexof ("."), H.length ()-1); //Upload files by path (modify path to change where files are stored in the server)Part.write (path + "\ \" +fname); //Prompt for upload successPrintWriter out =Response.getwriter (); Out.println ("); Out.println ("<title> Upload file </title>); Out.println ("<body>"); Out.println ("); Out.println ("</body>); }}I think the most critical statement is part, = Request.getpart ("FileName"); I understand the part interface as the file itself, part.write (path + "\ \" + fname); It is understood that the part follows the path in parentheses, where the path is the name of the file, the equivalent of a box, while part is the actual file content in the box.
The method of obtaining a file suffix is noteworthy.
Small white to: Upload files to the server using Request.getpart () in the Web
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