void (*isr_handle_array[50]) (void); How do you understand this statement??

This is an array of function pointers. It's good to peel one layer at a layer.

is an array of pointers to the return value of the void parameter and also void. First look inside [50] know is the array, and then look outward is a function pointer, together is a function pointer arrays. I write a source code, you will understand.

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#include <stdio.h>//这是你问题中的函数指针数组void(*isr_handle_array[50])(void); //这是两个返回值void 参数也是void的函数voidhello(void) { printf ("hello ");}voidworld(void) { printf("world\n");}intmain(){//这里把hello 和world两个函数的地址保存到数组中isr_handle_array[0] = hello;isr_handle_array[1] = world;//这里就可以通过数组直接调用函数啦。isr_handle_array[0]();isr_handle_array[1]();return0;}

The following results are performed:

Hello World

void (*isr_handle_array[50]) (void); How do you understand this statement??