JSON serialization and deserialization in C #

JSON serialization and deserialization helper classes:

Using system;using system.collections.generic;using system.linq;using system.text;using System.runtime.serialization;using system.runtime.serialization.json;using system.io;using System.text.regularexpressions;using system.web.script.serialization;namespace HelpClass.TypeHelp{//<summary  >///When you need to add a reference System.Web.Script.Serialization in VS, please refer to System.Web.Extensions//</summary> public class first Jsonhelp {//<summary>///JSON serialization (not binary)///</summary>//<typeparam        Name= "T" ></typeparam>//<param name= "T" ></param>//<returns></returns> public static string jsonserializer<t> (T-t) {JavaScriptSerializer jsonserialize = new Java            Scriptserializer ();        return Jsonserialize.serialize (t); }///<summary>///JSON deserialization (not binary)///</summary>//<typeparam name= "T" >   </typeparam>     <param name= "jsonstring" ></param>///<returns></returns> public static T J Sondeserialize<t> (String jsonstring) {JavaScriptSerializer jsonserialize = new Javascriptserializ            ER ();        Return (T) jsonserialize.deserialize<t> (jsonstring); }///<summary>///JSON serialization (binary mode, entity class using [Serializable])////</summary>//<type param name= "T" ></typeparam>//<param name= "T" ></param>//<returns></return s> public static string jsonserializerio<t> (T t) {DataContractJsonSerializer ser = new            DataContractJsonSerializer (typeof (T)); using (MemoryStream ms = new MemoryStream ()) {ser.                WriteObject (MS, T); String jsonstring = Encoding.UTF8.GetString (ms.                ToArray ()); Ms.                Close ();            return jsonstring;              }    }///<summary>///JSON deserialization (binary method, entity class using [Serializable])///</summary>//&lt ; Typeparam name= "T" ></typeparam>//<param name= "jsonstring" ></param>//<returns& gt;</returns> public static T jsondeserializeio<t> (String jsonstring) {DATACONTRACTJ            Sonserializer ser = new DataContractJsonSerializer (typeof (T)); using (MemoryStream ms = new MemoryStream (Encoding.UTF8.GetBytes (jsonstring))) {T obj = (t) ser.                ReadObject (MS);            return obj; }        }    }}

The above class uses two JSON serialization forms.

1. Use System.Web.Script.Serialization for serialization and deserialization, but when you need to add a reference System.Web.Script.Serialization in VS, refer to System.Web.Extensions first.

How to use:

(1) Classes that need to be serialized and deserialized

public class ddd{Public        string D1 {get; set;}        public string D2 {get; set;}        public string D3 {get; set;}}

(2) serialization and deserialization

Serialize a single class as JSON:

DDD A = new DDD {d1 = "1", D2 = "2", D3 = "3"};string stra = helpclass.typehelp.jsonhelp.jsonserializer<ddd> (a);dd D dd2 = helpclass.typehelp.jsonhelp.jsondeserialize<ddd> (stra); Serialization class sequence is a JSON array: ddd A = new DDD {d1 = "1", D2 = "2", D 3 = "3"};ddd B = new DDD {d1 = "one", D2 = "", D3 = "23"};ddd C = new DDD {d1 = "+", D2 = "$", D3 = ""}; List<ddd> ABC = new list<ddd> (); ABC. Add (a); ABC. ADD (b); ABC. ADD (c); string strabc = helpclass.typehelp.jsonhelp.jsonserializer<list<ddd>> (ABC); List<ddd> ddabc =helpclass.typehelp.jsonhelp.jsondeserialize<list<ddd>> (STRABC);

2. Using the DataContractJsonSerializer class under the System.Runtime.Serialization.Json namespace for JSON serialization and deserialization, the method uses the binary way to serialize and deserialize, and the class method needs to be used in the corresponding entity The corresponding identity in the class (for example: [DataContract] [DataMember (Name = "")]) is described in the following call.

How to use:

(1) Classes that need to be serialized and deserialized

[Datacontract]public class ddd{            [DataMember (Name = "D1")] public            string D1 {get; set;}            [DataMember (Name = "D2")]            public string D2 {get; set;}            [DataMember (Name = "D3")]            public string D3 {get; set;}}

(2) serialization and deserialization

Serialize a single class as JSON:

DDD A = new DDD {d1 = "1", D2 = "2", D3 = "3"};string stra = helpclass.typehelp.jsonhelp.jsonserializer<ddd> (a);dd D dd2 = helpclass.typehelp.jsonhelp.jsondeserialize<ddd> (stra); Serialization class sequence is a JSON array: ddd A = new DDD {d1 = "1", D2 = "2", D 3 = "3"};ddd B = new DDD {d1 = "one", D2 = "", D3 = "23"};ddd C = new DDD {d1 = "+", D2 = "$", D3 = ""}; List<ddd> ABC = new list<ddd> (); ABC. Add (a); ABC. ADD (b); ABC. ADD (c); string strabc = helpclass.typehelp.jsonhelp.jsonserializer<list<ddd>> (ABC); List<ddd> ddabc =helpclass.typehelp.jsonhelp.jsondeserialize<list<ddd>> (STRABC);

After reading the above, perhaps you have a certain understanding of JSON serialization and deserialization, write it here today, next time to summarize the serialization and deserialization of XML.

JSON serialization and deserialization in C #