Getting started with Cuda-combining OPNCV and Cuda programming (2) __ Programming

Source: Internet
Author: User

OpenCV read the picture and pass the picture data to Cuda processing

#include <iostream> #include <opencv2/core/core.hpp> #include <opencv2/highgui/highgui.hpp> #
Include<opencv2/imgproc/imgproc.hpp> #include <stdio.h> using namespace std;


using namespace CV; #define NUM_BLOCK//number of thread blocks #define Num_thread __global__ void Hello (Uchar *a, Uchar *b 
    , int bins,int nthreads, int nblocks) {int i;  int idx = blockidx.x*blockdim.x+threadidx.x;   
		Sequential thread index across the blocks for (I=IDX; i<bins; i+=nthreads*nblocks) {A[IDX]+=B[IDX];
		if (a[idx]>255) a[idx]=255;
    if (a[idx]<0) a[idx]=0;
	}} int main () {iplimage* img1=cvloadimage ("Test1.jpg", 0);
	iplimage* img2=cvloadimage ("Test2.jpg", 0); 
	uchar* a= (uchar*) img1->imagedata; 
	uchar* b= (uchar*) img2->imagedata;
	int n=img1->height*img1->widthstep;  
    Uchar *ad;  
    Uchar *BD;  
    const int csize = n*sizeof (Uchar);     
   
   
    const int isize = n*sizeof (Uchar);Cudamalloc ((void**) &ad, csize);   
    Cudamalloc ((void**) &bd, isize);   
    cudamemcpy (AD, A, csize, cudamemcpyhosttodevice);   
     
	CUDAMEMCPY (BD, B, Isize, cudamemcpyhosttodevice);  DIM3 Dimgrid (num_block,1,1);  Grid Dimensions dim3 dimblock (num_thread,1,1);  
    Block Dimensions Hello<<<dimgrid, dimblock>>> (AD, Bd,n,num_thread, Num_block); 

    cudamemcpy (b, AD, CSize, cudamemcpydevicetohost);  
    Cudafree (AD);  	


    Cudafree (BD);
    Cvnamedwindow ("Image display", cv_window_autosize);
    Cvshowimage ("Image display", IMG2);
	Cvwaitkey (0);
 
return 0; }
Reference code: Calculate PI

#include <stdio.h> #include <windows.h> #include <cuda.h> #define NBIN 1000000000//Number of bins #def
INE Num_block//number of thread blocks #define NUM_THREAD//number of threads per BLOCK int tid;

float pi = 0; Kernel that executes on the CUDA device __global__ void Cal_pi (float *sum, int nbin, float step, int nthreads, int nblo
	CKS) {int i;
	float x;  int idx = blockidx.x*blockdim.x+threadidx.x;
		Sequential thread index across the blocks for (I=IDX; i< nbin; i+=nthreads*nblocks) {x = (i+0.5) *step;
	SUM[IDX] + = 4.0/(1.0+x*x);  
}}//main routine that executes on the host int Main (void) {Large_integer frec;  
Large_integer STRT;  
Large_integer Ed;  
QueryPerformanceFrequency (&AMP;FREC);  
	QueryPerformanceCounter (&AMP;STRT);  DIM3 Dimgrid (num_block,1,1);  Grid Dimensions dim3 dimblock (num_thread,1,1);  Block Dimensions float *sumhost, *sumdev;  Pointer to host & device arrays float step = 1.0/nbin; Step sizE size_t size = num_block*num_thread*sizeof (float);  Array Memory Size Sumhost = (float *) malloc (size);  Allocate Array on host Cudamalloc ((void * *) &sumdev, size);
	Allocate array on device//Initialize array in device to 0 cudamemset (sumdev, 0, size);  Do calculation on device Cal_pi <<<dimgrid, dimblock>>> (Sumdev, Nbin, step, Num_thread, NUM_BLOCK); Call CUDA kernel//Retrieve result from device and store it in host array cudamemcpy (Sumhost, Sumdev, size, Cudamem
	Cpydevicetohost);
	for (tid=0; tid<num_thread*num_block; tid++) pi + = Sumhost[tid];

	Pi *= step;

	Print results printf ("PI =%f\n", pi); 
	Cleanup free (sumhost);	         


 Cudafree (Sumdev); 

QueryPerformanceCounter (&ed); printf ("%e\n", (ed. Quadpart-strt.quadpart) *1000/frec.  
	QuadPart);
return 0;
 }


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