Go by Example:pointers

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The go language supports pointers, allowing you to pass variable values through references within the program.

Package Mainimport "FMT"//We use two functions: Zeroval and zeroptr to demonstrate the use of pointers//Zeroval functions have an int type parameter, this time passed to the function is the value of the variable. Zeroval gets a ival copy value from which function it is called. Func zeroval (ival int) {    ival = 0}//The argument to the ZEROPTR function is an int type pointer, which means a pointer passed to an int of the function. The *iptr from its memory address in the function body to obtain the current value corresponding to this address. Assigning a pointer to an dereference will change the value of the real address referenced by the pointer. Func zeroptr (iptr *int) {    *iptr = 0}func Main () {    I: = 1    fmt. Println ("initial:", i)    zeroval (i)    FMT. Println ("Zeroval:", i)//    by using the & operator to obtain the memory address of the variable///For example: &i is the pointer to the variable i    zeroptr (&i)    FMT. Println ("Zeroptr:", i)    //pointer type can also be printed out of the    FMT. PRINTLN ("pointer:", &i)}

Output

$ go Run pointers.goinitial:1zeroval:1zeroptr:0pointer:0x42131100

其中 zeroval in the main cannot be changed in a function i 's value, but zeroptr Yes, because it has a reference to the memory address of this variable.

Next example: Go by example:structs

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