HDU-1403 Suffix Array Preliminary

Test instructions: Find the longest common substring of two strings
Two strings are concatenated and then a height array is obtained.
Note that the two SA values must be on a different side
The subject is used to test the template, think of Qingdao that overturned feeling very bad

#include <iostream>#include <algorithm>#include <cstdio>#include <cstring>#include <cstdlib>#include <cmath>#include <string>#include <vector>#include <stack>#include <queue>#include <set>#include <map>#define REP (i,j,k) for (register int i=j;i<=k;i++)#define RREP (i,j,k) for (register int i=j;i>=k;i--)#define EREP (i,u) for (register int i=head[u];~i;i=nxt[i])#define IIN (a) scanf ("%d", &a)#define Lin (a) scanf ("%lld", &a)#define DIN (a) scanf ("%lf", &a)#define S0 (a) scanf ("%s", a)#define S1 (a) scanf ("%s", a+1)#define PRINT (a) printf ("%lld", (ll) a)#define ENTER Putchar ('\n ')#define Blank Putchar (")#define PRINTLN (a) printf ("%lld\n ", (ll) a)#define IOS ios::sync_with_stdio (0)using namespaceStdConst intMAXN =1e6+11;Const intOO =0x3f3f3f3f;Const DoubleEPS =1e-7;typedef Long LongLl;ll Read () {ll x=0, f=1;Register CharCh=getchar (); while(ch<' 0 '|| Ch>' 9 '){if(ch=='-') f=-1; Ch=getchar ();} while(ch>=' 0 '&&ch<=' 9 ') {x=x*Ten+ch-' 0 '; Ch=getchar ();}returnX*f;}CharSTR[MAXN];structsa{intRANK[MAXN],SA[MAXN],TSA[MAXN],A[MAXN],B[MAXN];intCNTA[MAXN],CNTB[MAXN];intheight[maxn],best[maxn][ -],n;//height[i]: CP of Sa[i] and Sa[i-1]    voidGet () {N=strlen (str+1); Rep (I,0, -) cnta[i]=0; Rep (I,1, n) cnta[str[i]]++; Rep (I,1, -) cnta[i]+=cnta[i-1]; Rrep (I,n,1) Sa[cnta[str[i]]--]=i; rank[sa[1]]=1; Rep (I,2, N) {if(Str[sa[i]]==str[sa[i-1]]) {Rank[sa[i]]=rank[sa[i-1]]; }Else{rank[sa[i]]=1+rank[sa[i-1]]; }        } for(intL=1; rank[sa[n]]<n;l<<=1) {Rep (I,1, N) cnta[i]=cntb[i]=0; Rep (I,1, n) cnta[a[i]=rank[i]]++; Rep (I,1, N) cntb[b[i]= (i+l<=n? RANK[I+L]:0)]++; Rep (I,1, N) cnta[i]+=cnta[i-1],cntb[i]+=cntb[i-1]; Rrep (I,n,1) Tsa[cntb[b[i]]--]=i; Rrep (I,n,1) Sa[cnta[a[tsa[i]]]--]=tsa[i]; rank[sa[1]]=1; Rep (I,2, N) {BOOLFlag=a[sa[i]]==a[sa[i-1]]&&b[sa[i]]==b[sa[i-1]];                Flag=!flag; Rank[sa[i]]=rank[sa[i-1]]+flag; }        }    }voidHT () {intj=0; Rep (I,1, N) {if(j) j--; while(Str[i+j]==str[sa[rank[i]-1]+J]) J + +;        Height[rank[i]]=j; }    }voidRMQ () {Rep (I,1, N) best[i][0]=height[i]; for(intI=1;(1<<i) <=n;i++) { for(intj=1; j+ (1<<i)-1<=n;j++) {best[j][i]=min (best[j][i],best[j+ (1<< (i-1))][i-1]); }        }    }intQueryintLintR) {if(L==R)return-oo;if(l>r) swap (L,R); l++;intK=LOG2 (r-l+1);returnMin (best[l][k],best[r-(1&LT;&LT;K)+1][k]); }}sa;CharSTR1[MAXN];intMain () { while(~S1 (str)) {intLen=strlen (str+1);        S1 (STR1); strcat (str+1, str1+1);        Sa.get (); Sa.ht ();intN=strlen (str+1);intans=0; for(inti =1; I <= N; i++) {if(Ans<sa.height[i]) {if((sa.sa[i]<=len&&sa.sa[i-1]>len) | | (Sa.sa[i]>len&&sa.sa[i-1]<=len)) {ans=sa.height[i];    }}} println (ANS); }return 0;}

HDU-1403 Suffix Array Preliminary