Hdu 2060 Snooker (Math Problem)

Hdu 2060 Snooker (Math Problem)

Question: There are n balls on the table. One score is a and the other score is B. Ask if the score can be exceeded (or equal to) if the first person scores all n balls) the second person.

Analysis: 1. If n> 6, there are 6 colored balls and a n-6 of red balls on the table. Every time you hit a red ball, you have to make up a black ball.

(N-6) * 1 + (n-6) * 7 + 2 + 3 + 4 + 5 + 6 + 7

2. If n is <= 6, then there are n values left on the table, for example, when n = 1, there will be one black ball left, and the score for n is

(7 + 7-n + 1) * n/2.

Code:

 

#include
 
  #include
  
   using namespace std;int main(){    int n,a,b;    int t;    scanf("%d",&t);    while(t--)    {        scanf("%d%d%d",&n,&a,&b);        if(n>6)        {            if(a+(n-6)*1+(n-6)*7+2+3+4+5+6+7>=b)            {                printf("Yes\n");            }            else                printf("No\n");        }        else        {            if(a+(7+7-n+1)*n/2>=b)                printf("Yes\n");            else                printf("No\n");        }    }    return 0;}