How does the Python language implement dictionary ordering?

Xinhua dictionary Everyone has used it, then how to use the Python language is to implement the dictionary sort? Follow this tutorial to learn the Python implementation of the dictionary based on the value sort, need a friend to refer to it

The specific contents are as follows:

Use sorted to sort dictionaries by their value size

>>> record = {' A '::100}>>>, ' B ': sorted, ' C ': The ", ' d '," (Record.items (), Key=lambda x:x[1]) [(' B ', 86), (' A ', ","), (' C ', "), (' d ', 100)]

Sorted the first parameter can be iterated, it can be a tuple, a list

>>> items = [(1, ' B '), (1, ' a '), (2, ' a '), (0, ' B '), (0, ' a ')]>>> sorted (items) [(0, ' B '), (0, ' a '), (1, ' A '), (1, ' B '), (2, ' a ')]

Why (0, ' B ') in front of (0, ' a ')?

Because uppercase letters in ASCII code precede lowercase letters, use the Str.lower () method to change their order

>>> sorted (items, Key=lambda x: (X[0], X[1].lower ()))
[(0, ' a '), (0, ' B '), (1, ' a '), (1, ' B '), (2, ' a ')]