How to obtain the file name of the current executable file in Linux

In many cases, we place the resource file in the relative location of the executable file, for example, with the executable file. Therefore, it is necessary to obtain the absolute path of the current executable file and then find the path of the resource file.

In Windows, you can use getmodulefilename to obtain the name of the current executable file, but in Linux, this situation becomes more complex.

First, I have not found a similar function. I can only use argv [0] to obtain the executable file name. In Linux, there is a disgusting and cute link/Symbol link. For example, you can convert/usr/local/evol3d/demo.exe ln into/usr/bin/ev-bin. At this time, you will be dumpfounded to execute ev-bin.

After several days of consultation, I finally found a simple method:

1. When the current program is running, you can read/proc/self/EXE, which is a connection to the executable file of the current process. This link points to a result similar to getmodulefilename. I would like to thank my former male colleague, the beautiful Fang girl.

2. readlink function. readlink can convert the connection name to the actual file name.

 

Note: This method is purely created by an individual and tested correctly on the machine. If any, please kindly advise.

The Code is as follows.

STD: String _ exename = "/proc/self/EXE ";
Size_t linksize = 256;
Char exename [256] = {0 };
If (readlink (_ exename. c_str (), exename, linksize )! =-1)
{
_ Exename = exename;
}

Printf ("application file name = % s! /N ", _ exename. c_str ());