How to shift the result of regular PHP replacement

Source: Internet
Author: User
$str = "; $a =preg_replace ('/\_data=[\" |\ ') ([a-za-z0-9\_]+) ([\s\] \ ']* '/eis ', "data_array (' \\1 ')", $str);d ie ($a); function Data_array ($key) {$code =add_div ("$key"); return "$code";} function Add_div ($v) {  $value = "";  return "$value";}


The results obtained
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>
>
>
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The desired result

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Reply to discussion (solution)

The difference between the two results is not seen!

$a =preg_replace ('/\s+\_data=[\ ' |\ '] ([a-za-z0-9\_]+) ([\s\] \ ']* ' >/eis ', "data_array (' \\1 ')", $str);d ie ($a); function Data_array ($key) {    $code =add_div ($key);    return $code;   } function Add_div ($v) {         $value = ">";      return $value;   }

$a =preg_replace ('/\s+\_data=[\ ' |\ '] ([a-za-z0-9\_]+) ([\s\] \ ']* ' >/eis ', "data_array (' \\1 ')", $str);d ie ($a); function Data_array ($key) {    $code =add_div ($key);    return $code;   } function Add_div ($v) {         $value = ">";      return $value;   }





Ask: If my HTML is this form, how should I change the

$str = '

';

The desired result

***********************************************************************************************************
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$str = '

'; $a =preg_replace_callback ('/< (\w+) \s+\_data=[\ "|\"] ([a-za-z0-9\_]+] ([\s\] \ ']*) \s*class= "(. +?)" ><\/\1>/is ', "Data_array", $str);d ie ($a); function Data_array ($key) { $code =add_div ($key [4], $key [2]); return $code; } function Add_div ($class, $id) { $value = ""; return $value; }

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