How to understand this code: void (* signal (int sinno, void (* func) (int), sinnofunc

How to understand this code: void (* signal (int sinno, void (* func) (int), sinnofunc

Void (* signal (int sinno, void (* func) (int)

Let's take a look at void (* func) (int). here it means to declare a function pointer func. Its Parameter type is int. The parameter name can be omitted without writing. Of course (int x) that's right.

Declare a function pointer signal, which has two parameters: int sinno and void (* func) (int ).

The signal function has its own parameter type int, omitting the parameter name: void (* signal (int sinno, void (* func) (int x) that's right !!

The Return Value Type of the signal function is void.

 

This introduction is easy to understand ~~~~