i++ traps in Java

Interview Trap questions:

int i=0=i++;

At this point I value:

I end up being 0;

When executing i=i++, the assignment symbol has the lowest priority and executes the i++ first;

Execute i++, the program first put I value 0 into the stack, and then the I to operate + +;

After i++ i is 1;

Finally, the assignment is performed, the data in the stack is 0 popped, assigned to I, again i is 0;

Therefore, best practice one: Do not assign values of the same variable more than once in a single expression.

i++ traps in Java