Initialization order in Java

/**
 * 1, when using a new object instance or calling a static member variable or method, initialize the static variable
 * 2, the static variable is initialized first in the initialization, the static block and the static variable are treated identically (during initialization, when there is a new object instance, Temporarily stop the static variable initialization after)
 * 3, when a static variable is not initialized, the default initial value (such as int 0)
 * 4, a new object instance is assigned to a non-static member variable, and so does the building block, which is preceded by the initialization of
 * 5, When a member variable is not initialized, use the default initial value (such as int 0)/public
class Testinit {
	private int i = print ("Member variable Assignment");
	{
		print ("Building block");
	}
	private static int J = Print ("Static variable Assignment");
	static {
		print ("static block");
	}
	private static Testinit ti1 = new Testinit ("Ti1");
	private static int k = 0;
	Public Testinit (String str) {
		System.out.println ("K:" + ++k + "	" + str + "	I:" + i++);
	}
	private static Testinit Ti2 = new Testinit ("Ti2");
	
	private static int print (String str) {
		System.out.println ("K:" + ++k + "	" + str + "	J:" + j + +);
		return j;
	}
	
	public static void Main (string[] args) {
		new Testinit ("Init");
	}

Results:

K:1	static variable assignment	j:0
k:2	static block	j:1
k:3	member variable assignment j:2 k:4	construction block	j:3
k:5	ti1	i:3
k:1	member variable assignment	j:4
k:2	construction block j:5
k:3 ti2 i:5 k : 4	member variable assignment	j:6
k:5	construction block	j:7
k:6	init	i:7