INT () argument must be a string or a number, not 'simplelazyobject'

Source: Internet
Author: User

The following problems are encountered today:

Medias_all = media. objects. filter (Q (is_delete = 0), Q (media_name _ contains = query) | Q (media_id _ contains = query )). order_by ("add_date") medias = medias_all.filter (user = request. user)

The following error occurs:

INT () argument must be a string or a number, not 'simplelazyobject'

Google, http://stackoverflow.com/questions/15878860/int-argument-must-be-a-string-or-a-number-not-simplelazyobject said like this:

The likely cause is that you're settingUser = request. User, Where request. user is not a real user object, but a simplelazyobject instance. seedjango:
Purpose of Django. utils. Functional. simplelazyobject? For more details, but usingRequest. User. IDShocould fix your issue.

Therefore, modify it:

Medias = medias_all.filter (user_id = request. User. ID)

Solve the problem.

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