ios-app Jump

1. Apply a jump

-  (ibaction) openwangyi {        // 1. Get Application Object     UIApplication *app = [UIApplication sharedApplication];     // 2. Create an application that needs to be opened url    //  in the application jump,  as long as there is a protocol header,  Path optional     #warning   protocol header in Project settings-info-url types settings     nsurl *url  = [nsurl urlwithstring:@ "wangyi://"];    // 3. Open URL with Application     if  ([App canopenurl:url])  {         // 3.1 determine if you can open         [app openURL:url];     }else    {        // 3.2 Open App  store Download         nslog (@ "Open app store based on App id");     }}

2. Appdelegate Agent for application jump

/** *   call  * *   @param  application  current application when opened by another application via URL   *   @param  url          Open url * * of the current program    @return   Successful processing  */-  (BOOL) Application: (uiapplication *) application  Handleopenurl: (nsurl *) url{    // 1. Get Home Controller      uinavigationcontroller *nav =  (uinavigationcontroller *) Self.window.rootViewController;     UIViewController *vc = nav.topViewController;         nslog (@ "%@",  url);    //  decide which URL to use to open the,  to make the appropriate processing ( Jump to the appropriate controller)     NSString *urlStr = url.absoluteString;     if  ([urlstr hasprefix:@ "Sina://login"])  {                 //  intercept the application that opened our program scheme        nsrange range = [ urlstr rangeofstring:@ "Sina://login?myscheme="];        nsstring  *scheme = [urlStr substringFromIndex:range.length];                 nslog (@ "Jump to Authorization Interface aaaaaaaaa %@",  scheme);//         if  ([Vc iskindofclass:[viewcontroller class])  == yes)  {#warning   Performseguewithidentifier via sb show jump method, transfer scheme             [vc performseguewithidentifier:@ "Home2accounts"  sender:scheme];//        }             }else if  ([urlstr hasprefix:@ "sina://view?id="])      { &nbSp;      nslog (@ "Jump to Detail Interface bbbbbbbbbb");         [vc performseguewithidentifier:@ "Home2detail"  sender:nil];             }        return yes;} A new method after #warning  ios7/** *   called (new method) when it is opened by another application via a URL  * *   @param   application        Current Applications  *   @param  url                 Open the url *  @ of the current program param sourceapplication  Open the current program's bundle identifier *   @param  annotation  * *   @return   successfully processed  */-  (BOOL) Application: (uiapplication *) application  openurl: (nsurl *) Url sourceapplication: (nsstring *) Sourceapplication annotation: (ID) annotation{#warning   NOTE:   If a new method is implemented,  old method old fails     /*     sourceapplication use:       when we do some advertising,  integration wall and other promotion when,  can take advantage of this unique Table a record of which program the current program is being promoted open     */     nslog (@ "%@ %@",  url, sourceapplication);     //  1. Get home controller     UINavigationController *nav =  (Uinavigationcontroller  *) self.window.rootviewcontroller;    uiviewcontroller *vc =  Nav.topviewcontroller;        nslog (@ "%@",  url);     //  determine which URL opens the,  to make the appropriate processing (jump to the appropriate controller)     NSString *urlStr  = url.absolutestring;    if  ([urlstr hasprefix:@ "Sina://login"])  {                 //  Intercept the application that opened our program Scheme        nsrange range = [urlstr rangeofstring:@ "Sina://login?myScheme="];         NSString *scheme = [urlStr  substringfromindex:range.length];                 nslog (@ "Jump to Authorization Interface  %@",  scheme);         //        if  ([vc iskindofclass:[viewcontroller  Class]] == yes)  {        [vc  performseguewithidentifier:@ "Home2accounts"  sender:scheme];         //        }             }else if  ([urlstr hasprefix:@ "sina://view?id="])      {        nslog (@ "Jump to Detail Interface"); &NBsp;       [vc performseguewithidentifier:@ "Home2detail"  sender: nil];            }         return yes;}

3.prepareForSegue Controller Jump

Prepareforsegue Show connect jump. must be controller jump controller, cannot control jump controller

-(void) Prepareforsegue: (Uistoryboardsegue *) Segue Sender: (ID) sender{NSLog (@ "Home%@", sender);    Uiviewcontroller *VC = Segue.destinationviewcontroller;  if ([VC Iskindofclass:[tableviewcontroller Class]]) {//if the target controller of the jump is authorized, it is necessary to set scheme Tableviewcontroller *TBVC        = VC;    Tbvc.callscheme = sender; }}

Ios-Apply Jump