JAVA | and |, & amp; and & amp;

JAVA | and |, and the difference
The differences between these four operators can be easily distinguished by names: | (short circuit or), | (OR), & (short circuit and), & (by bit and) here is a simple example:

public class Test1 {        public static void main(String[] args) {           int i=0;           if (3>2 || (i++)>0){              System. out .println(i);           }       }}

The reason why the I value output by this program is 0 is | when judging, if the previous judgment is true, it will no longer judge whether the subsequent statements are true, then the subsequent statements will not be executed.
If you change | to |, what will happen?

public class Test1 {        public static void main(String[] args) {           int i=0;           if (3>2 | (i++)>0){              System. out .println(i);           }       }}

The result output I value is 1, because | when the operator is determining whether or not the previous expression is true, it will execute the following statement, the value of I is increased by 1 to 1.

public class Test2 {        public static void main(String[] args) {               // TODO Auto-generated method stub               int i=0;           if ((i++>2) && (i++)>2){                        System. out .println("i=" +i);           } else {              System. out .println(i);           }       }}

The value of result output I is 1 because the & operator determines that the entire expression is false when the first expression is false, the following statement will not be executed.
Replace & &

public class Test2 {        public static void main(String[] args) {               // TODO Auto-generated method stub               int i=0;           if ((i++>2) & (i++)>2){                        System. out .println("i=" +i);           } else {              System. out .println(i);           }       }}

The reason for the result output I value is 2 is that & the judgment results of the front and back expressions are compared, SO 2 is output.