Java Fundamentals: Exception capture Order

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Public voidtestexception () {int a[] = {1,2,3};int q = 0;try{for (int i=0;i<a.length;i++) {a[i]/= q;}} catch (ArithmeticException h) {System.out.print ("arithmeticexception\n");        Run}catch (Exception e) {System.out.print ("exception\n");        Will not run. and must be placed behind the ArithmeticException/** * The larger exception must not only be placed in the back * and placed in the back will not be run (by the earlier range of the smaller * abnormal intercept), then what is the point??? */}finally{system.out.print ("finally\n");}} <span style= "color: #3333ff;" >output</span>arithmeticexceptionfinally

 *        Key points1:despiteArithmeticExceptioninherit fromException. But when it happensArithmeticExceptionException

 *                         and captures it, it simply captures the actual occurrence of the exception. Not because Exception is its parent class and

  *                          run exception that catch clause.

  *         Essentials 2 : But suppose you try to have a larger range exception catch statement put to catch

* Catch clause unreachable Error " Unreachablecatch block for ArithmeticException.

* Itis already handled by the catch block for Exception "

  *                          ( parent " must be placed behind, assuming there are no inheritance relationships, for example Span style= "font-family:"times New roman"" >classnotfoundexception

 *                         and the ArithmeticException of the Catch there is no relationship between clauses.

Java Fundamentals: Exception capture Order