Java integer divide to get floating point type

1  Public classtestfloatordouble {2 3      Public Static voidMain (string[] args) {4Point NUM1 =NewPoint (84, 250);5Point num2 =NewPoint (21, 10);6         7         floatF1 = (num1.y-num2.y)/(num1.x-num2.x);8         floatF2 = (float) (NUM1.Y-NUM2.Y)/(num1.x-num2.x);9         Ten         DoubleD1 = (num1.y-num2.y)/(num1.x-num2.x); One         DoubleD2 = (Double) (NUM1.Y-NUM2.Y)/(num1.x-num2.x); A          - System.out.println (F1); - System.out.println (F2); the          - System.out.println (d1); - System.out.println (D2); -     } + } -  + classpoint{ A     intx; at     inty; -      -      PublicPoint (intXinty) { -          This. x =x; -          This. y =y; -     } in}

Output:

3.03.80952383.03.8095238095238093

It's starting to get a little out of the way. Why the first one is 3.0 the second is 3.8 ....

This is actually F1. The resulting order is that (NUM1.Y-NUM2.Y)/(num1.x-num2.x) divide two integers, get an integral type, temporarily assume int result, and then convert result to float type, so there is a 3.0

The resulting order of F2 is that (float) (NUM1.Y-NUM2.Y) first converts the first number to float, and then divides it with float and int to get the float type

Java integer divide to get floating point type