Java +tomcat + SPRINGMVC for page access

2018-07-18 14:38:29
WINDOW7 installation Record of Java environment:
First, install Tomcat
1, download Tomcat 7.0, unzip, no installation, put to directory: D:\apache-tomcat-7.0.90.
2, configure the system environment variable, catalina_base=d:\apache-tomcat-7.0.90,catalina_home=d:\apache-tomcat-7.0.90, add "%CATALINA_HOME" in Path %\lib;%catalina_home%\bin "Environment variable.
3. Enter D:\apache-tomcat-7.0.90\bin, execute startup Tomcat, enter "127.0.0.1:8080" in the browser to see if it is successful.
Second, use SPRINGMVC build page
1, use idea to create SPRINGMVC project, WebAppTest2

2, modify the Web/web-inf/web.xml URL rule to accept All

<?xml version= "1.0" encoding= "UTF-8"? ><web-app xmlns= "Http://xmlns.jcp.org/xml/ns/javaee" xmlns:xsi= "http ://www.w3.org/2001/XMLSchema-instance "xsi:schemalocation=" Http://xmlns.jcp.org/xml/ns/javaee/http Xmlns.jcp.org/xml/ns/javaee/web-app_4_0.xsd "version=" 4.0 "> <context-param> <param-name>c Ontextconfiglocation</param-name> <param-value>/WEB-INF/applicationContext.xml</param-value> & Lt;/context-param> <listener> <listener-class>org.springframework.web.context.contextloaderlisten er</listener-class> </listener> <servlet> &LT;SERVLET-NAME&GT;DISPATCHER&LT;/SERVLET-NAME&G        T            <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <init-param> <param-name>contextConfigLocation</param-name> <param-value>classpath:dispatcher-ser Vlet.xml</param-value>        </init-param> </servlet> <servlet-mapping> &LT;SERVLET-NAME&GT;DISPATCHER&LT;/SERVL Et-name> <url-pattern>/</url-pattern> </servlet-mapping></web-app>

3. Create a dispatcher-servlet.xml file under src

<?xml version= "1.0" encoding= "UTF-8"? ><beans xmlns= "Http://www.springframework.org/schema/beans" xmlns:       Xsi= "Http://www.w3.org/2001/XMLSchema-instance" xmlns:context= "Http://www.springframework.org/schema/context" Xmlns:mvc= "Http://www.springframework.org/schema/mvc" xsi:schemalocation= "Http://www.springframework.org/schema /beans http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema/ Context Http://www.springframework.org/schema/context/spring-context-4.1.xsd http://www.springframework.org/ Schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-4.1.xsd "> <!--Scan the package and the sub Packa GE--<context:component-scan base-package= "test"/> <!--don ' t handle the static resource--&LT ; Mvc:default-servlet-handler/> <!--If you use annotation you must configure following setting--&LT;MVC : Annotation-driven/> <!--Configure the Internalresourceviewresolver--<bean class= " Org.springframework.web.servlet.view.InternalResourceViewResolver "id=" Internalresourceviewresolver "> & lt;! ---prefix---<property name= "prefix" value= "/web-inf/jsp/"/> <!--suffix--<property na Me= "suffix" value= ". jsp"/> </bean></beans>

4. Create the test directory under SRC and create the Mycontroller file in the directory.

package test;import org.springframework.stereotype.Controller;import org.springframework.web.bind.annotation.RequestMapping;@Controller@RequestMapping("/mvc")public class MyController {    @RequestMapping("/hello")    public String hello(){                return "hello";    }}

5. Create the classes and Lib folders under Web/web-inf to set the compiled. class file directory and the third-party dependency package directory.

6. Create the JSP directory under web/web-inf/and create the hello.jsp in the directory

<%@ page contentType="text/html;charset=UTF-8" language="java" %>

7, Fight the war package Build-->build artifacts, package name WebAppTest2, put into the D:\apache-tomcat-7.0.90\webapps directory.
8. Restart Tomcat to access Http://127.0.0.1:8080/webAppTest2/mvc/hello.

9, can also set idea built-in Tomcat, direct idea within the launch browser


10, omit the project name, direct Access can


Java +tomcat + SPRINGMVC for page access