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the//sort () method is used to sort the elements of the array.
//Syntax: Arrayobject.sort (sorty)
//sortby: Optional. Specifies the sort order. Must be a function.
//return value, a reference to an array, note that arrays are sorted on the original array, and no replicas are generated.
//note: If a parameter is not used when calling the method, the elements in the array are sorted alphabetically
//To sort, to say the exact point, is to sort by character encoding order. To implement
///This, you should first convert the elements of the array to a string (if necessary),
//For comparison.
//If you want to sort by other criteria, you need to provide a comparison function that
//To compare two values, and then return a relative order that describes the two values, comparing
the//function should have two parameters A and B with the following return values:
//If A is less than B, a value that is less than 0 is returned if a should appear before B in the sorted array.
//If a equals B, the value 0 is returned.
//If A is greater than B, a value greater than 0 is returned.
//1. Create an array and sort alphabetically.
var arr1 = new Array (6);
arr1[0] = "George";
arr1[1] = "John";
arr1[2] = "Thomas";
arr1[3] = "James";
arr1[4] = "Adrew";
arr1[5] = "Martin";
document.write (arr1 + "<br/>");
document.write (Arr1.sort () + "<br/>");
var arr2 = new Array (6);
arr2[0] = "ten";
arr2[1] = "5";
arr2[2] = "Max";
arr2[3] = "+";
arr2[4] = "n";
arr2[5] = "1";
document.write (arr2 + "<br/>");
document.write (Arr2.sort () + "<br/>");
The above code does not sort the numbers by the size of the numeric values, and to achieve this, a sort function must be used:
function Sortnumber(a, b) {
return A- b;
}
var arr3= new Array (6);
arr3[0] = "ten";
arr3[1] = "5";
arr3[2] = "Max";
arr3[3] = "+";
arr3[4] = "n";
arr3[5] = "1";
document.write (arr3 + "<br/>");
document.write (Arr3.sort (sortnumber)+ "<br/>");
</script>
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JavaScript sort () method
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