Leetcode Compare Version Numbers

Compare numbers version1 and version1.
If version1 > version2 return 1, if version1 < version2 return-1, otherwise ret Urn 0.

Assume that the version strings is non-empty and contain only digits and the . character.
The . character does not represent a, decimal point and was used to separate number sequences.
For instance, was not "both and 2.5 a half" or "half-to-version three", it is the fifth Second-level revision of the S Econd first-level revision.

Here are an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37


Solution:

2, using "." When separating, add "\ \."
3, the default is 0 when the array is not assigned a value

Package Leetcode;public class Compareversionnumbers {public    int compareversion (string version1, String version2) { C1/>string[] Ver1=version1.split ("\ \");    String[] Ver2=version2.split ("\ \");    int Maxlength;if (ver1.length>=ver2.length) {        maxlength=ver1.length;    }    else{       maxlength=ver2.length;    }    int[] Ints1 = new Int[maxlength];            for (int i=0; i < maxlength; i++) {            Ints1[i] = Integer.parseint (Ver1[i]);        }        int[] ints2 = new Int[maxlength];        for (int i=0; i < maxlength; i++) {            Ints2[i] = Integer.parseint (Ver2[i]);        }        for (int i=0;i<maxlength;i++) {        if (Ints1[i]>ints2[i]) {        return 1;        }        else if (Ints1[i]<ints2[i]) {        return-1;        }        }        return 0;}    }

　　

Leetcode Compare Version Numbers